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Gennadij [26K]
3 years ago
5

What is​ 3/5 ​written as a percent? A 3.5% B 30% C 35% D 60%

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
6 0
D is the correct answer.
Brut [27]3 years ago
4 0
The correct answer to this would be D.) 60%
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an actor will earn d dollars this year. His agent Collects a Commission of 10% of all his earnings. which expression shows how m
Naya [18.7K]

Answer: d - (d x .1)

Step-by-step explanation: The expression that will show how much the actor will earn is d - (d x .1). D is the actor’s earnings and d x .1 is the commission of their agent.

7 0
3 years ago
For every $12 Maria earns babysitting, she donates $2 to the local pet shelter. Last week, Maria earned a total of $60. Of the $
insens350 [35]
Answer is $14, I think.
4 0
3 years ago
3<br> 6<br> Choose 1 answer<br> A<br> = 27<br> B<br> = 4<br> C2=5<br> D<br> r = 18
olasank [31]

Answer:

B

Step-by-step explanation:

I hope this helped!

8 0
3 years ago
Read 2 more answers
The graph shows two lines, A and B. A graph is shown with x- and y-axes labeled from 0 to 6 at increments of 1. A straight line
maxonik [38]

there will be one solution because the lines intersect at exactly one set of points.

(0,6)(6,3)
slope(m) = (3-6) / (6-0) = -3/6 = -1/2

y = mx + b
6 = -1/2(0) + b
6 = b
y = -1/2x + 6

(0,0)(6,6)
slope(m) = (6-0) / (6-0) = 6/6 = 1

y = mx + b
6 = 1(6) + b
6 = 6 + b
6 - 6 = b
0 = b

y = x + 0

x = -1/2x + 6
1/2x + x = 6
1/2x + 2/2x = 6
3/2x = 6
x = 6/(3/2)
x = 6 * 2/3
x = 12/3 = 4

<span>solution is : (4,4)</span>
6 0
4 years ago
The LB Company has long manufactured a light bulb with an average life of 5400 hours. Company researchers have recently develope
elena55 [62]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the average life of light bulbs.

As per given , we have

Null hypothesis : H_0 : \mu =5400

Alternative hypothesis : H_a : \mu >5400

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Formula for Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

\sigma=population standard deviation

For n=95,\ \overline{x}=5483\ \&\ \sigma=500, we have

z=\dfrac{5483-5400}{\dfrac{500}{\sqrt{95}}}=1.61796786124\approx1.6180

Using z-value table , Critical one-tailed test value for 0.06 significance level :

z_{0.06}=1.5548

 Decision : Since critical z value (1.5548) < test statistic (1.6180), so we reject the null hypothesis .

[We reject the null hypothesis when critical value is less than the test statistic value .]

Conclusion : We have enough evidence at 0.06 significance level to support the claim that the new filament yields a longer bulb life

8 0
4 years ago
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