The images represent sexual and asexual reproduction. The offspring in ages A and C are identical to the parents while the offsp
ring produced in images A and D will vary from the parents. What processes account for the genetic variation in images A and D?
A) pollination and fertilization
B) meiosis, mitosis, and mutation
C) production of gametes via meiosis and fertilization
D) production of sex cells via mitosis and zygote development via fertilization
A) pollination and fertilization
B) meiosis, mitosis, and mutation
C) production of gametes via meiosis and fertilization
D) production of sex cells via mitosis and zygote development via fertilization
2 answers:
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Answer: The cross will produce 4 offsprings with the following genotypes:
XhXh, XhX, XhY and XY.
Explanation: Hemophilia is an X-linked disease. A woman who carries the hemophilia gene but doesn't not express it is heterozygous, therefore she has a genotype of XhX, and a man who has hemophilia has a genotype of XhY. A cross between them will produce one female and one male who are hemophilic (XhXh and XhY), one female who is a carrier (XhX) and one normal male.
See the punnett square attached for the cross
