Answer:
16
Step-by-step explanation:
The triangle AEC is a right triangle and 2 sides are already filled in.
The hypotenuse is 10 and one side is 6.
So, this is a 3-4-5 right triangle.
Thus, the remaining side EC is 8.
Since EC is congruent to ED, then segment CD is 8+8=16
The completely factored equation is (a²b - 5)(4a²b - 1)
<h3>How to factor equation?</h3>
4a⁴b² - 21a²b + 5 = 0
let's expand the equation
Therefore,
4a⁴b² - 21a²b + 5 = 0
4a⁴b² - 20a²b - a²b + 5 = 0
Rearrange the equation
4a⁴b² - a²b - 20a²b + 5 = 0
Let's factorise the equation
4a⁴b² - a²b - 20a²b + 5 = 0
a²b(4a²b - 1) - 5(4a²b - 1) = 0
Therefore, the completely factored equation is as follows:
a²b(4a²b - 1) - 5(4a²b - 1) = 0
(a²b - 5)(4a²b - 1)
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y=2(3)x+1
−
y=2(3)x
y-y=2(3)x+1−2(3)x
the answer would be 0=1
but if it is asking u if it is false or true it is
0=1 is false, therefore the system of equations has no solutions