12%
$68 - 59.9 = $8.1
$8.1/$68 = 0.11911764705
0.11911764705 x100 = 11.911764705
11.911764705 is rounded up to 12
12%
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
n+18
Step-by-step explanation:
A number n just means a variable n, and since we are increasing it (or adding to it), by 18, it is n+18
