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scoundrel [369]
3 years ago
12

A statement which checks to see if the value of the expression on the left side is the same as the value of the expression on th

e right side is an example of the use of the
Mathematics
1 answer:
aksik [14]3 years ago
8 0

Answer:

<h2>A relational statement</h2>

Step-by-step explanation:

In computer programming relational operators are used to check conditions, that is if one conditions matches another and returns true if the condition is met or satisfied.

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If the product ab is 0, then either a or b must be
algol [13]
0 because 0 times anything is 0
8 0
4 years ago
H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

(h-k)(3)=3^2+1-3+2

(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0
3 years ago
Estimate each product 5/7×1/9=
Cerrena [4.2K]
Multiply it out to get 5/7*1/9=5/63.  This is an exact value of the product.
8 0
3 years ago
What is the 51st term of the arithmetic sequence 29,9,-11
valina [46]

Answer:

-951

Step-by-step explanation:

an=a1+(n−1)d

\begin{gathered}29 = a_1 + (1-1)d\\29 = a_1\\9 = 29 + (2-1)d\\9 = 29 + d\\d = -20\\a_n = 29 -20 (n-1)\\a_n = 29 - 20n+20\\a_n = -20n + 49\\\\a_51 = -20(51) + 49 = -951\end{gathered}29=a1+(1−1)d29=a19=29+(2−1)d9=29+dd=−20an=29−20(n−1)an=29−20n+20an=−20n+49a51=−20(51)+49=−951

6 0
3 years ago
Solve for x <br> Find ADB<br> Find BDC
NeTakaya

Answer:

x=12 ADB= 56 BDC= 54

Step-by-step explanation:

ADB and BDC are complementary, so they add up to 90 degrees. In other words ADB+BDC= 90 So I can input my knowns into the equation

(3x+10) + (4x-4) = 90

I combined like terms to give me 7x+6=90

Then I subtract 6 from both sides giving me 7x=84

Last I divide 7 on both sides. x=12

Then I input the x (12) into the equation and solve it from there

3(12)+10 and 4(12)-4

3(12)+10=56

4(12)-4=54

. . . I think. Hope this helps!

5 0
3 years ago
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