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den301095 [7]
3 years ago
8

QUICK 100 POINTS AND BRAINLIST ANSWER QUICK

Mathematics
2 answers:
ycow [4]3 years ago
6 0

Answer:

lol my question was deleted ima have 50 more points!

Step-by-step explanation:

irina1246 [14]3 years ago
3 0

Answer:

Part A:

The y-intercept is $1,500

The x-intercept is 20 days

Part B:

Equation of the line in point-slope form is  y - 1350 = -75×(x - 2)

Equation of the line in slope-intercept form is y = -75·x + 1500

Equation of the line in standard form  is y + 75·x = 1500

Part C:

f(x) = -75·x + 1500

Part D:

$1,125

Step-by-step explanation:

The information given are;

x,                 g(x)

0,                 $1,500

2,                 $1,350

4,                 $1,200

The equation of a straight line relation between the x, and y, coordinates in slope and intercept form is  y = m·x + c

Where;

m = The slope ,

c = The y-intercept

From the data, we have two points, (x₁, y₁), (x₂, y₂) given as (0, 1,500), (2, 1350);

The y-intercept = y at x = 0 = 1,500

y = -75·x + 1500

x = 1500/75 = 20

Part B:

The equation in point-slope form is y - y₁ = m×(x - x₁)

Which gives;

Equation of the line in point-slope form is  y - 1350 = -75×(x - 2)

Equation of the line in slope-intercept form is y = -75·x + 1500

Equation of the line in standard form  is y + 75·x = 1500

Part C:

The equation of the line using function notation is f(x) = -75·x + 1500

Part D:

The balance in the bank after 5 days is f(5) = -75 × 5  + 1500 = $1,125

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$140

Step-by-step explanation:

Given:

P(getting scholarship A)=0.05

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Select the correct answer from each drop-down menu.
Alenkasestr [34]

Answer:

The points of intersections are: <u>(1.5 , 1.25) and (4 , 0)</u>

Step-by-step explanation:

Given:

y = x² - 6x + 8   ⇒ (1)

2y + x = 4         ⇒ (2)

And required the solution of the system of equations.

By graphing the system of equations, the points of intersections are:

<u>(1.5 , 1.25) and (4 , 0)</u>

See the attached figure.

<u>Another solution:</u>

By substitution of y from the second equation at the first equation.

From (1) ⇒ y = 0.5 (4-x)

At (2): and solve for x

0.5 ( 4 - x ) = x² - 6x + 8 ⇒ multiply both sides by 2

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2x² - 12x + 16 + x - 4 = 0

2x² - 11x + 12 = 0

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so, a = 2 , b = -11 and c = 12

∴x=\frac{-(-11) \pm \sqrt{(-11)^2-4*2*12} }{2*2}=\frac{11 \pm \sqrt{25} }{4} =\frac{11 \pm 5}{4} \\x = \frac{11+5}{4} = \frac{16}{4}=4\\  OR \  x = \frac{11-5}{4}=\frac{6}{4}=1.5\\

∴ at x = 4       ⇒ y = 0.5 (4-x) = 0.5 * 0 = 0

And at x = 1.5 ⇒ y  = 0.5 (4-x) = 0.5 * ( 4 - 1.5 ) = 0.5 * 2.5 = 1.25

<u>So, the solution are the points (4,0) and (1.5 , 1.25)</u>

6 0
3 years ago
Given the function f(x) = 4(x+3) − 5, solve for the inverse function when x = 3. (1 point)
atroni [7]

the function f(x) = 4(x+3) − 5

Lets find the inverse function f^-1(x)

step 1: Replace f(x) with y

y = 4(x+3) − 5

step 2: Replace x  with y and y with x

x = 4(y+3) - 5

step 3: Solve for y

x = 4(y+3) - 5

x = 4y +12 -5

x= 4y + 7 (subtract 7 on both sides)

x - 7 = 4y (divide by 4 on both sides)

\frac{x-7}{4}=y

f^{-1}(x)=\frac{x-7}{4}

Given : x = 3

We plug in 3 for x in the inverse function

f^{-1}(x)=\frac{3-7}{4} = -1

the inverse function when x = 3  is -1


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