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Elina [12.6K]
3 years ago
14

A boy is building a pyramid out of building blocks. He puts 20 blocks in the first row, then he puts 19 blocks in the row above,

and so on. Find the total number of blocks he needs.
Mathematics
1 answer:
rjkz [21]3 years ago
8 0

Answer:

<h3>The answer is 206 I believe</h3>

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Evaluate 6+2•3-1 A) 23 B)16 C)10 D)11
Ratling [72]

6 + 2 * 3 - 1

2 * 3 = 6

6 + 6 - 1

6 + 6 = 12

12 - 1 = 11

D) 11

7 0
3 years ago
Read 2 more answers
A pile of sand has been stored in the shape of a cone. Mr. Terwilliker knows that the pile is 20 feet tall and 102 feet in circu
xenn [34]

Answer:

The area of tarpaulin is 1315.63 ft^2.  

Step-by-step explanation:

height, h = 20 feet

circumference, C = 102 feet

Let the radius is r.

Circumference, C = 2 x 3.14 x r = 102

r = 16.24 feet

Let the slant height is L.

L = \sqrt{h^2 + r^2}\\\\L = \sqrt{20^2 + 16.24^2}\\\\L = 25.8 ft

The curved surface area is

S = 3.14 x r x L

S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2

4 0
3 years ago
A line passes through the point (-6,7) and has a slope of -3/2 write in point slope form
Neko [114]
Y - y1 = m(x-x1)
y - 7 = -3/2(x + 6)
7 0
3 years ago
A delivery truck is transporting boxes of two sizes large and small. The combined weight of a large box and a small box is 80 po
Liula [17]

Answer:

small=15 large=40

Step-by-step explanation:

x=large box

y=small box

55 = x + y

 

50x + 55y = 2825

 

50x + 55( 55 - x) = 2825

 

50x + 3025 - 55x = 2825

 

0 = 55x - 50 x + 2825 - 3025

 

0 = 5x - 200

 

200 = 5x

 

x=40

 

y = 15

7 0
3 years ago
A rectangle or piece of paper has a width is 3 inches less than its link it is cut in half along a diagonal to create two congru
kolezko [41]

The length and width of the rectangle is 11 in and 8 in respectively.

Step-by-step explanation:

Given,

The width of a rectangle is 3 in less than the length.

The area of each congruent right angle triangle = 44 in²

To find the length and width of the rectangle.

Formula

The area of a triangle with b base and h as height = \frac{1}{2}bh

Now,

Let, the width = x and the length = x+3.

Here, for the triangle, width will be its base and length will be its height.

According to the problem,

\frac{1}{2}×(x+3)×x = 44

or, x^{2} +3x = 88

or,x^{2} +3x-88 = 0

or, x^{2}+(11-8)x-88 = 0

or, x^{2}+11x-8x-88 =0

or, x(x+11)-8(x+11) = 0

or, (x+11)(x-8) = 0

So, x = 8 ( x≠-11, the length or width could no be negative)

Hence,

Width = 8 in and length = 8+3 = 11 in

3 0
3 years ago
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