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ser-zykov [4K]
2 years ago
11

I need help on these please I really need help. It's tomorrow.

Mathematics
1 answer:
alekssr [168]2 years ago
8 0
Mean: add all the values together and divide by how many numbers there are.
Example- 2+4+6+8+10=30
30/5=6. The mean is 6

Median: arrange the numbers in order from least to greatest (counting order). If there is more than one of any number make sure to put them all together. Then find the number in the middle. That's the median. If there isn't one number in the middle, take the two 'middle' numbers, add them together and divide by 2. That will be the median
Ex- 2, 4, 6, 8, 10 median is 6
Ex- 2, 4, 6, 8, 10, 12 6+8=14 14/2=7 median is 7

Mode: what number shows up the most often? Sometimes there might not be a mode if there are no repeated values.
Ex- 2, 4, 6, 6, 8, 10 the mode is 6, it is in the list more than any other number

Range: the difference of the greatest value and least value
Ex- 2, 4, 6, 8, 10 10-2=8. The range is 8
One thing that is the MOST helpful when finding all of these is to put all the numbers in counting order (least to greatest) before you try to do anything!

Sorry I can't be more specific, it's difficult to read the graphs and charts
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Answer:

This should explain it

Step-by-step explanation:

If its the graph question I think it is this is the answer screenshot.

4 0
3 years ago
Can someone please help me? I solved all the sides but when I add it up I don't get any of the options :(
aivan3 [116]
292

please mark brainliest?? :)
8 0
3 years ago
Please Help!!! Evaluate the following <br><br> 2/((3-(3-1))*3-1)
antiseptic1488 [7]
2/ 3 - (3 - 1) * 3 - 1 = -4
Simplify
= 2/-4
which is
= -2/4 
Then simplify again
= -1/2
6 0
3 years ago
1/3 of Murka’s age is twice as much as Ivan’s age. What is the ratio of Murka’s age to Ivan’s age?
Korvikt [17]

Answer:

6:1

Step-by-step explanation:

4 0
3 years ago
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
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