Answer:
6.13
Step-by-step explanation:
Using Sine Law we know that
Using your figure let's assign sides and angles:
A=? B = 60° C = 70°
a = 5 b = ? c = x
If we put that into our formula:
Notice that we have too many unknowns. We need to complete at least one ratio to do this, so how do we do this?
Notice we have 2 angles given, so we solve for the third angle. The sum of all angles in any triangle is always 180°
∠A + ∠B + ∠C= 180°
∠A + 60° + 70° = 180°
∠A + 130° = 180°
∠A = 180° - 130°
∠A = 50°
Now we can use this to solve for x.
So the closest answer would be 6.13
First we need to find the slope:
Slope formula=
Plug in your given values from the coordinate
Slope =
When we have 2 "-"'s together they turn into a + sign so we add.
Slope =
Slope =
Simplify (in this case divide) the slope:
Slope =
slope-intercept form is:
y=mx+b
Where m=slope
b=y-intercept
So far we have:
y=2x+b
To find b all we have to do is pick any given coordinate and plug it in:
I chose (3,1)
so we plug that in the equation
1=6+b
Now solve for b:
1=6+b
subtract 6 from both sides
b=-5
Final answer:
y=2x-5 (D)
Answer:
A) Central angle has same measure as intercepted arc.
- mCE = mCD + mDE = 20° + 90° = 110°
B) Opposite angles of cyclic quadrilateral are supplementary.
- mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
- m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
- m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
- mQP = 360° - (90° + 76° + 72°) = 122°
C)
- m∠MLN = m∠MRN as same arc MN is intercepted
- m∠LMN is right angle as opposite side is diameter.
- ∠MNL is complementary with ∠MLN which is same as ∠MRN
- m∠MNL = 90° - 47° = 43°
D) Tangent secant angle is half of the intercepted arc.
<em>It seems wrong. Should be mQP instead of mQR</em>
- mQP = 2*m∠RQP = 2*74° = 148°
The LCM is 2, Because 2*4=8 and 2*50=100 :)
