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3 years ago

PLEASE I NEED HELP! How do you find y?

Mathematics

1 answer:

myrzilka [38]3 years ago

4 0

In this example, y is equal to 8.

In order to find this, first note that the two x value expressions create a straight line. That means when we add them together they will equal 180. this will give us a value for x.

x + 10 + 10x - 61 = 180

11x - 51 = 180

11x = 231

x = 21

Now that we have the value of x, we can do the same for the straight line created by the x + 10 angle and the 18y + 5 angle.

x + 10 + 18y + 5 = 180

(21) + 10 + 18y + 5 = 180

36 + 18y = 180

18y = 144

y = 8

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zlopas [31]

Answer:

it is 3

Step-by-step explanation:

3×3487+7+7+8+8+8++7+7

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2 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

Identify this conic section. 16y = x^2

kiruha [24]

ANSWER

A parabola.

EXPLANATION

The given conic is :

$16y = {x}^{2}$

This can be rewritten as:

${x}^{2} = 16y$

${x}^{2} = 4(4)y$

This is a parabola with the vertex at the origin.

The foci is (0,4)

Therefore the given conic section is a parabola that has an axis of symmetry parallel to the y-axis.

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ololo11 [35]

Answer:

To find the quotient, you must start by dividing 25 into 1,658.

Step-by-step explanation:

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Answer:

The answer is C. 50%

Step-by-step explanation:

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3 years ago