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ollegr [7]
3 years ago
10

Consider a sample with a mean of 30 and a standard deviation of 5. Use Chebyshev's theorem to determine the minimum percentage o

f the data within each of the following ranges. (Round your answers to the nearest integer.) (a) 20 to 40 % (b) 15 to 45 % (c) 23 to 37 % (d) 17 to 43 % (e) 13 to 47
Mathematics
1 answer:
Ainat [17]3 years ago
8 0

Answer:

a) We are within 2 deviations from the mean since 30 -2*5 = 20 and 30 + 2*5 = 40. So our value for k = 2 and we can find the % like this:

\% = (1- \frac{1}{2^2}) *100 = 75\%

b) We are within 3 deviations from the mean since 30 -3*5 = 20 and 30 + 3*5 = 45. So our value for k = 3 and we can find the % like this:

\% = (1- \frac{1}{3^2}) *100 = 88.88\% \approx 89\%

c) We are within 1.4 deviations from the mean since 30 -1.4*5 = 23 and 30 + 1.4*5 = 37. So our value for k = 1.4 and we can find the % like this:

\% = (1- \frac{1}{1.4^2}) *100 = 48.97\% \approx 49\%

d) We are within 2.6 deviations from the mean since 30 -2.6*5 = 17 and 30 + 2.6*5 = 43. So our value for k = 2.6 and we can find the % like this:

\% = (1- \frac{1}{2.6^2}) *100 = 85.2\% \approx 85\%

e) We are within 3.4 deviations from the mean since 30 -3.4*5 =13 and 30 + 3.4*5 = 47. So our value for k = 3.4 and we can find the % like this:

\% = (1- \frac{1}{3.4^2}) *100 = 91.35\% \approx 91\%

Step-by-step explanation:

For this case we need to remember what says the Chebysev theorem, and it says that we have at least 1-\frac{1}{k^2} of the data liying within k deviations from the mean on the interval \bar X \pm k s

We know that \bar X= 30, s=5

Part a

For this case we want the values between 20 and 40

So we are within 2 deviations from the mean since 30 -2*5 = 20 and 30 + 2*5 = 40. So our value for k = 2 and we can find the % like this:

\% = (1- \frac{1}{2^2}) *100 = 75\%

Part b

For this case we want the values between 15 and 45

So we are within 3 deviations from the mean since 30 -3*5 = 20 and 30 + 3*5 = 45. So our value for k = 3 and we can find the % like this:

\% = (1- \frac{1}{3^2}) *100 = 88.88\% \approx 89\%

Part c

For this case we want the values between 23 and 37

So we are within 1.4 deviations from the mean since 30 -1.4*5 = 23 and 30 + 1.4*5 = 37. So our value for k = 1.4 and we can find the % like this:

\% = (1- \frac{1}{1.4^2}) *100 = 48.97\% \approx 49\%

Part d

For this case we want the values between 17 and 43

So we are within 2.6 deviations from the mean since 30 -2.6*5 = 17 and 30 + 2.6*5 = 43. So our value for k = 2.6 and we can find the % like this:

\% = (1- \frac{1}{2.6^2}) *100 = 85.2\% \approx 85\%

Part e

For this case we want the values between 13 and 47

So we are within 3.4 deviations from the mean since 30 -3.4*5 =13 and 30 + 3.4*5 = 47. So our value for k = 3.4 and we can find the % like this:

\% = (1- \frac{1}{3.4^2}) *100 = 91.35\% \approx 91\%

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<u>Final answer</u>:-

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