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2 years ago

Someone please help me. Serious answers only.

Mathematics

2 answers:

svetoff [14.1K]2 years ago

4 0

Your answer is C. F(n)=10<em>n</em> + 1
I thought it was a but the first 1 o and 1 interfered. 11 times 0 is zero but for C. it would still be 10 times 0 is 0 but then you add the one and it makes it true so you final answer is C.
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galina1969 [7]2 years ago

3 0

Hey there!

The answer should be C. F(n) = 10n + 1

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3 years ago

Question 13

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3 years ago

In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .

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Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

$\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}$

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

$\frac{k}{sin(K)}=\frac{j}{sin(J)} \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)} \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o \\$

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