The key difference between energy flow and matter cycling is that energy flow shows the energy transmission from one trophic level to next trophic level in food chains while matter cycling shows the flow or cycling of elements through the living and nonliving parts of ecosystems
Answer: c
Explanation: it dose not matter
The answer is false.
Deamination is the process (reaction) in which an amine group is removed from a molecule of amino acid. The enzymes that are involved in this reaction are called deaminases. Deamination can be used for energy(break down of amino acids), when there is too much protein intake. Amine group is converted to ammonia that is then converted to urea or uric acid in the urea cycle and at the end excreted through the urine.
In the human body, deamination occurs mostly in the liver (e.g. urea cycle), but also in the kidneys (deamination of glutamate).
Answer:
C) hematocrit is highest
Explanation:
The viscosity is the property of the fluid substance related to the flow of the resistance. The flow of the resistance increases when the amount of content in the fluid increases.
The flowing blood contains the water and the other components like the cells and proteins therefore it also exhibit the viscosity.
The viscosity in blood happens when the cells and molecules interact with each other therefore measure of these components indicated about the viscosity of the blood.
The hematocrit is the ratio of the proportion of the red blood cells present in the blood to the total volume of the blood.
The viscosity of blood, therefore, increases when the hematocrit is high and decrease when the hematocrit component is low.
Thus, Option-C is the correct answer.
The correct answer is this one: "C) Nnew = Nold + 2." A student is studying a process in which a diploid cell becomes haploid. The CORRECT mathematical model for the process if Nnew is the number of chromosomes in the haploid cell and Nold is the number of chromosomes in the diploid cell is this: <span>new = Nold + 2
</span>
Here are the choices.
<span>A)
Nnew = 2·Nold
B)
Nnew =
Nold
2
C)
Nnew = Nold + 2
D)
Nnew = Nold × 2</span>
