Perimeter (P) = 2 · Length(L) + 2 · Width (W) → P = 2L + 2W
Solve for either L or W (I am solving for L).
200 - 2W = 2L
(200 - 2W)/2 = L
100 - W = L
Area (A) = Length (L) · Width (W)
= (100 - W) · W
= 100W - W²
Find the derivative, set it equal to 0, and solve:
dA/dW = 100 - 2W
0 = 100 - 2W
W = 50
refer to the equation above for L:
100 - W = L
100 - 50 = L
50 = L
Dimensions for the maximum Area are 50 ft x 50 ft
Answer:
C: 9076.3 cm^3
Step-by-step explanation:
Use the formula for the volume of a cylinder.
V=πr^2 times h
h=25
Here, I'm assuming 21.5 cm is the diameter, so divide 21.5 cm by 2 to get 10.75 as r.
V=(10.75^2)π times 25
115.5625π times 25
This is about 2889π
This simplifies best to choice C, which is about 9076.3 cm^3
However, if I was wrong about 21.5 cm being the diameter, my answer is wrong. If 21.5 cm is r, choice D is the correct answer. If 21.5 cm is the diameter, C is the answer.
The answer to the equation is b -16
Answer:
Step-by-step explanation:
Step 1
we know that sinθ = opp/hyp
so
let x = hyp
sin(23.64) = 5.42/x
0.40=5.42/x
x0.40 = 5.42
x = 13.55
Thefore the length of the hypothenuse is 13.55 Send Love:333
