Lets make an equation for the line first. The slope is 3 and the y intercept is -1, so we can make the equation y = 3x - 1. Then, to figure out what sign to use (<= or >= due to solid line in graph), we replace the = sign with one and see if a coordinate in the shaded area will furfill the inequality. If it doesn't, we know it needs the other inequality sign. If it does, we have found the correct inequality. So let's try y <= 3x - 1 with the coordinate (1,1). We try it, solve, and get 1 <= 2. So, the inequality for this graph is y <= 3x - 1.
Check the picture below.
let's firstly convert the mixed fractions to improper fractions.
![\stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} ~\hfill \stackrel{mixed}{12\frac{1}{2}}\implies \cfrac{12\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{25}{2}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cstackrel%7Bmixed%7D%7B7%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B7%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B15%7D%7B2%7D%7D%20~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B12%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B12%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B25%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\stackrel{\textit{\Large Areas}}{\stackrel{two~triangles}{2\left[ \cfrac{1}{2}\left(\cfrac{15}{2} \right)(10) \right]}~~ + ~~\stackrel{\textit{three rectangles}}{(10)(15)~~ + ~~\left( \cfrac{15}{2} \right)(15)~~ + ~~\left( \cfrac{25}{2} \right)(15)}} \\\\\\ 75~~ + ~~150~~ + ~~112.5~~ + ~~187.5\implies \boxed{525}](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7Btwo~triangles%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%5Cleft%28%5Ccfrac%7B15%7D%7B2%7D%20%5Cright%29%2810%29%20%5Cright%5D%7D~~%20%2B%20~~%5Cstackrel%7B%5Ctextit%7Bthree%20rectangles%7D%7D%7B%2810%29%2815%29~~%20%2B%20~~%5Cleft%28%20%5Ccfrac%7B15%7D%7B2%7D%20%5Cright%29%2815%29~~%20%2B%20~~%5Cleft%28%20%5Ccfrac%7B25%7D%7B2%7D%20%5Cright%29%2815%29%7D%7D%20%5C%5C%5C%5C%5C%5C%2075~~%20%2B%20~~150~~%20%2B%20~~112.5~~%20%2B%20~~187.5%5Cimplies%20%5Cboxed%7B525%7D)
<em>Working together</em>, decorating 16 dozens of cookies will take 103 minutes.
<u>Let's calculate theor individual work rate</u> :
Felix's rate = 1/90
Oscar's rate = 1/120
Combined rate = 1/90 + 1/120 = (4 + 3) / 360 = 7/360
<u>Time taken for both of the to decorate 8 dozens</u> :
Reciprocal of their combined rate = 1 ÷ (7/360) = 51.428571 minutes
<u>Hence, the time taken to decorate 16 dozens will be</u> :
(16/8) × 51.428571 = 102.857 = 103 minutes (nearest while number).
Learn more :brainly.com/question/18796573
Answer:
The answer is "Option C"
Step-by-step explanation:
The using formula
→r = rate
→ n = compounded value
In choice a:
When compounded is monthly 
In choice b:
When compounded is quarterly
In choice c:
Whenn compounded is daily 
In choice d:
When compounded is semiannually
