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3 years ago

3. what are the approximate solutions of 2x^2-x+10=0? a. -2,2.5 b. -1.97,2.47 c. -2.5,2 d. no solution

Mathematics

1 answer:

Schach [20]3 years ago

7 0

The answer is D. no solution

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Write the equation of the line that passes through A(-3,-2) and B(1,6).

topjm [15]

Answer:

Step-by-step explanation:

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3 years ago

Determine the place value of the digit 3 in the whole number. 30,500,421

Bond [772]

Answer:

30,000,000 or Thirty million -------> Ten millions place

Step-by-step explanation:

Hope this helps!

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3 years ago

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In circle E with m DEF 36 and DE = 3 units find area of

deff fn [24]

Answer:

A ≈ 2.83 units²

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

= πr² × $\frac{36}{360}$

= π × 3² × $\frac{1}{10}$

= $\frac{9\pi }{10}$

≈ 2.83 units² ( to the nearest hundredth )

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3 years ago

What does 4/10 simplify to?

SIZIF [17.4K]

4/10 = 2/5

When you divide both the numerator and denominator by 2 you will get a new fraction of 2/5. This fraction is in simplest form because you can't reduce it further.
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3 years ago

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Find the orthogonal complement W⊥ of W and give a basis for W⊥. W = x y z : x = 1 2 t, y = − 1 2 t, z = 6t.

igor_vitrenko [27]

Answer:

W⊥= (a, b, c)

a = v - (1/2)w

b = v

c = w

Basis for W⊥ = <(1,1,0),(-1/2,0,1)>

Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

(x,y,z)·(a,b,c) = 0

ax + by + cz = 0

So, taking into account that x=12t, y=-12t and z=6t, the equation above is equal to:

12ta + -12tb + 6tc = 0

12a - 12b + 6c = 0

Then, if we made b=v and c=w and solve for a, we get:

12a - 12v + 6w = 0

a = (12v - 6w)/12

a = v - (1/2)w

Therefore, the orthogonal complement W⊥ of W has the form:

W⊥ = (a,b,c) = (v - (1/2)w, v, w)

On the other hand, we can write W⊥ as:

W⊥ = (v - (1/2)w, v, w)

W⊥ = (v,v,0) + ((-1/2)w,0,w)

W⊥ = v(1,1,0) + w(-1/2,0,1)

That means that we can write any vector of W⊥ as a linear combinations of the vectors (1,1,0) and (-1/2,0,1), so they are a basis for W⊥

7 0

3 years ago