Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
0.27 repeating.
Step-by-step explanation:
So to solve this we just have to use division.
1 clearly doesnt go into 3 at least one time, so we can add a decimal point and add a 0 to make it 30.
11 goes into 30 2 times, so we have:
0.2
and 30-22=8
So we can add another 0 and make it 80.
Then 11 goes into 80 7 times. So we have:
0.27
and 80-77=3
So again, add the 0, we have 30.
11 goes into 30 2 times, so:
0.272
and 30-22=8
Add another 0 we get 80.
11 goes into 80 7 times.
So finally, we have:
0.2727.
This is a repeating decimal.
This can be shown as:
0.<u>27</u>
So this is your answer!
I was a bit confused with which one it was on your answer key, but knowing that it is 0.<u>27</u> I am guessing you can chose!
Hope this helps!
<h3>
Answer: Choice B</h3>
Explanation:
Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.
Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.
Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.
Choice D is ruled out for similar reasoning as choice A. Recall that 