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earnstyle [38]
4 years ago
8

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.24 mg of mercury. A sample of 25 bulbs shows a m

ean of 3.29 mg of mercury.
(a) State the hypotheses for a right-tailed test, using GreenBeam’s claim as the null hypothesis about the mean.
Mathematics
1 answer:
amm18124 years ago
3 0

Answer:

Null hypothesis:\mu \leq 3.24  

Alternative hypothesis:\mu > 3.24  

Step-by-step explanation:

1) Previous concepts  and data given

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A right tailed test (sometimes called an upper test) is when the alternative hypothesis statement contains a greater than (>) symbol.

\bar X=3.29 represent the sample mean  

s represent the sample standard deviation

n represent the sample selected

\alpha significance level  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean for fluorescent bulbs is no more than 3.24 mg of mercury, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.24  

Alternative hypothesis:\mu > 3.24  

IIf we know the population deviation we can apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

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Mrs. Ross needs to buy dish soap. There are four differently sized containers. Sort the brands from least to the greatest unit p
r-ruslan [8.4K]

Answer: Spotless soap < Bright wash < Lemon bright < lot of suds

Step-by-step explanation:

Given that 8 oz of Lots of suds cost = $0.98

Then unit price of 1 lot of suds = 0.98/8 = $0.1225

Given that 12 oz of Bright wash cost = $1.29

Then unit price of 1 Bright wash = 1.29/12 = $0.1075

Given that 30 oz of Spotless soap cost = $3.14

Then unit price of 1 Spotless soap = 3.14/30 = $0.104666666667

Given that 32 oz of Lemon bright cost = $3.50Then unit price of 1 Lemon bright = 3.50/32 = $0.109375

We also need to round the values to the nearest thousandth means three digits after decimal

Then unit price of 1 lot of suds = $0.123

unit price of 1 Bright wash = $0.108

unit price of 1 Spotless soap = $0.105

unit price of 1 Lemon bright = $0.109

Now we can easily sort them

0.105 < 0.108 < 0.109 < 0.123

respective names in sorted order are:

Spotless soap < Bright wash < Lemon bright < lot of suds

8 0
3 years ago
Why would a bank want to loan someone money?
AVprozaik [17]

Answer: So they can help someone with good credit score

Step-by-step explanation:

4 0
3 years ago
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The shapes nelow are shaded to show two different fraftions, Are the fractions equivalent? Use the drop down menus to best expla
katovenus [111]

Answer:

Yes they are equivalent.

Step-by-step explanation:

They each represent one half.

5 0
3 years ago
If 2x-y equals 120, what are the values of x and y?
krek1111 [17]
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Shortly after their arrival, Europeans began introducing pigs to the Americas as a source of food. Some escaped, and others were
natka813 [3]

Answer: About 800 thousand

The more accurate value is 807,528 but this is also an approximation.

=======================================================

Work Shown:

t = \text{number of years since the year 2000}

P_0 = \text{population (in millions) in the year 2000}

P = P_0(1.2)^t\\\\5 = P_0(1.2)^{10}\\\\5 \approx P_0*6.1917364224\\\\P_0 \approx \frac{5}{6.1917364224}\\\\P_0 \approx 0.80752791444922\\\\P_0 \approx 0.807528\\\\

That's the rough population of wild pigs (in millions) for the year 2000.

Multiply by 10^6 to get it in terms of units instead.

0.807528\times10^6 = 807,528

There were roughly 800 thousand wild pigs in the year 2000.

7 0
2 years ago
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