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Arlecino [84]
3 years ago
6

Kira brought chocolate and vanilla cupcakes to school for her birthday. 80 students decided to take a cupcake, and 32 of them pi

cked vanilla. What percentage of the students picked a vanilla cupcake?
Mathematics
1 answer:
Paladinen [302]3 years ago
5 0

Answer:

40%

Step-by-step explanation:

Percentage of students that picked a vanilla cupcake = (students that picked a vanilla cupcake / total number of students)x 100

(32 / 80) x 100 = 40%

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lesya692 [45]

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Step-by-step explanation:

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6 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
3 years ago
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ValentinkaMS [17]

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

pr.nepaltheyouyouyouyouyouyouyouyouyouyouyouisisisyouyouyou

8 0
2 years ago
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Write the equation of the line that contains the points (4, −7) and (1, 5). The slope of the line that contains the points (4, −
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Slope = (5+7)/(1-4) = 12/-3 = -4

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equation
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3 years ago
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