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Arlecino [84]
3 years ago
6

Kira brought chocolate and vanilla cupcakes to school for her birthday. 80 students decided to take a cupcake, and 32 of them pi

cked vanilla. What percentage of the students picked a vanilla cupcake?
Mathematics
1 answer:
Paladinen [302]3 years ago
5 0

Answer:

40%

Step-by-step explanation:

Percentage of students that picked a vanilla cupcake = (students that picked a vanilla cupcake / total number of students)x 100

(32 / 80) x 100 = 40%

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The movie theater received a shipment of candy boxes in a carton that has a volume of about 64,000 cubic inches. Each candy box
vova2212 [387]
Volumen carton= 64000 inches³
 Volume of a candy box= 6 inx 5 inx 1/2 
 Volume of a candy box=15 inches³

 Then, you have that the total candy boxes in the carton is:

 x=640000 inches³/15 inches³
 x=4267 candy boxes

 About how many candy boxes are in the carton? There are 4267 candy boxes
 


4 0
3 years ago
Read 2 more answers
PLEASE someone tell me this correct or not !!!!!!!!!!!!!!! WILL MARK BRIANLIEST CORRECT ANSWER !!!!!!!!!!!!
Goryan [66]

Answer:

i think its correct

i think someone else just had this same question tho so ill double check

Step-by-step explanation:

4 0
3 years ago
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What is i^22 if i^2 is -1
Sever21 [200]
I^22 equals to -1 since i^2 is negative one
4 0
3 years ago
|x−7 |=x−7<br> plz help show steps
Scilla [17]

Answer:

All numbers from 7 and up (x is greater than or equal to 7)

Step-by-step explanation:

|7-7| =7-7

0=0

|8-7|=8-7

1=1

BUT

|6-7| =/= 6-7

1 =/= -1

4 0
4 years ago
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A 200-liter tank initially full of water develops a leak at the bottom. Given that 20% of the water leaks out in the first 5 min
Leya [2.2K]

Answer:

127.53 liters left after 10 minutes

Step-by-step explanation:

Let

A \to Amount

t \to time

Given

A(0) = 200 --- initial

A(5) = 200 * (1 - 20\%) = 160 --- the amount left, after 5 minutes

Required

A(10) --- amount left after 5 minutes

To do this, we make use of:

A(t) = A(0) * e^{kt}

A(5)  = 160 implies that:

160 = 200 * e^{k*5}

Divide both sides by 200

0.80 = e^{k*5}

Take natural logarithm of both sides

\ln(0.80) = \ln(e^{k*5})

\ln(0.80) = \ln(e^{5k})

\ln(0.80) = 5k\ln(e)

So, we have:

-0.223 = 5k

Divide by 5

k = -0.045

So, the function is:

A(t) = A(0) * e^{kt}

A(t) = 200 * e^{-0.045t}

The amount after 10 minutes is:

A(10) = 200 * e^{-0.045*10}

A(10) = 200 * e^{-0.45}

A(10) = 127.53

3 0
3 years ago
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