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horrorfan [7]
2 years ago
15

Please help, I will give brainliest.

Mathematics
2 answers:
mojhsa [17]2 years ago
4 0

Answer:

8 \frac{3}{10}

Step-by-step explanation:

first, make the fractions have common denominators:

8 \frac{4}{5} - \frac{1}{2} = 8 \frac{8}{10} - \frac{5}{10}

Then, subtract:

8\frac{8}{10} - \frac{5}{10}= 8\frac{3}{10}

Serjik [45]2 years ago
3 0

Answer:

8.8-0.5=8.3 or 8 3/10

Hope This Helps!!!

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Please help! I will mark you as brainliest!
lisov135 [29]

Answer:

7/9

Step-by-step explanation:

Think of 1 as being 9/9. The difference between 9/9 and 2/9 is 7/9, which is the answer

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Plz helppp<br><br> Use Distributive Property to Solve for x<br><br> 4 (x + 3)=8
11Alexandr11 [23.1K]

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x=-1...

have a great day

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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
1 year ago
(GIVING EXTRA POINTS ON THIS ONE!! IM ALSO GIVING AWAY BRAINLIEST TO WHO EVER HELPS ME OUT :D)
nasty-shy [4]

Answer:

Step-by-step explanation:

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3 years ago
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What is the answer? Please help me!!! PLEASE!!!!
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Answer:

a.) y=1/3x +3

Step-by-step explanation:

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