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strojnjashka [21]
3 years ago
9

How many significant figures are there in the number 31.6901? A. 6 B. 4 C. 3 D. 5

Mathematics
2 answers:
Simora [160]3 years ago
5 0
Significant figures are numbers after the decimal point, which have usually been rounded. There are four numbers after the decimal point, so there are 4 significant figures.

:)

alexira [117]3 years ago
3 0

Answer:it’s 6


Step-by-step explanation:


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Write seventeen thousand and one hundred six thousandths in standard form.
ICE Princess25 [194]


When you see the word 'and' that's where you have to put the decimal when writing a number in standard form.

 So you would write this number as 17,000.106

Hope this helps. :)

3 0
2 years ago
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Stacy exercises 3 days each week by walking around the soccer field near her home the field is 80 yards wide and 115 yards long
zhenek [66]

a: draw a rectangle an label one side 80 and the other 115

b: 1560 Yards

6 0
3 years ago
Use these similar triangles on the coordinate plane to determine the equation of a straight line with a slope of 5/3 that passes
Zina [86]

Answer:

y=5/3x

Step-by-step explanation:

5 0
3 years ago
Type the correct answer in the box. express your answer to two significant figures. a reaction between 1.7 moles of zinc iodide
irga5000 [103]

The percent yield of zinc carbonate is 5.91%.

<h3>What is chemical reaction?</h3>

The chemical reaction is the reaction between two reactants which led to the formation of products.

The products are substances which forms after reaction. The reactants are the substances which are original materials.

Given is a reaction between 1.7 moles of zinc iodide and excess sodium carbonate yields 12.6 grams of zinc carbonate.

The given balanced equation is:  Na₂CO₃ + ZnI₂ → 2NaI + ZnCO₃

From given moles of zinc iodide, the moles of zinc carbonate

1.7 moles of ZnI₂ = 1.7 moles of ZnCO₃

Molar mass of zinc carbonate is 125.38 g/mol

Theoretical yield =  1.7 moles of ZnCO₃ x  125.38 g/mol = 213.15 g  ZnCO₃

Theoretical yield is 213.15 g and the actual yield is given as 12.6 g.

percent yield = [ 12.6 g / 213.15 g  ZnCO₃ ] x 100

percent yield = 5.91%

The percent yield of zinc carbonate is 5.91%.

Learn more about chemical reaction.

brainly.com/question/22817140

#SPJ1

7 0
2 years ago
SOLVE
Sauron [17]

Answer:

approximately

1623.6

Step-by-step explanation:

16 1/2%=.165 which is approximately equal to 1/6, so we can just multiply the original number by 6.

7 0
3 years ago
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