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docker41 [41]
3 years ago
14

A group of six tourists arrive at an airport gate 15 minutes before flight time, but only two seats are available.

Mathematics
2 answers:
melomori [17]3 years ago
8 0
8 different groups are aloud in the plane

Margaret [11]3 years ago
4 0
Only one group of two people can get on the plane and two groups of two cannot get on the plane.
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At winds speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 100
alisha [4.7K]

Answer:

Lower limit = 1007.95 cm/s

Upper limit = 1142.05 cm/s

Step-by-step explanation:

We have to calculate a 95% CI with population's standard deviation known.

The sample is size n=60, with mean M=1075.

The confidence interval can be expressed as:

M-z*\sigma/\sqrt{n} \leq\mu\leq M+z*\sigma/\sqrt{n}

For a 95% CI, the value of z=1.96.

1075-1.96*265/\sqrt{60} \leq\mu\leq 1075+1.96*265/\sqrt{60} \\\\1075-67.05 \leq\mu\leq 1075+67.05\\\\ 1007.95 \leq\mu\leq 1142.05

8 0
3 years ago
Can I have some help
Brums [2.3K]

\frac{100}{40}  =  \frac{z + 69}{z}  \\ 100z = 40z  + 2760 \\ 60z = 2760 \\ z = 46
6 0
3 years ago
Can anyone please help!!!
quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

8 0
2 years ago
What's the square root of 2 rounded to the nearest tenth ?
vichka [17]
It is 1.4 when rounded
8 0
3 years ago
Read 2 more answers
Each member of a nine-person committee attends any given meeting of the committee with probability 1/2. What is the probability
Tatiana [17]
A suitable statistics calculator gives the probability that 6 or more show up as being about ...
  0.2539

4 0
3 years ago
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