suppose a parabola has an axis of symmetry at x=-2, a maximum height of 8, passes through the point (-6, 2). Wrire the equation
of the parabola in vertex form.
1 answer:
Answer:
y = -3/8(x + 2)^2 + 8
Step-by-step explanation:
vertex form is
y = a(x - b)^2 + c where a is a constant and (b,c) is the vertex.
The maximum is at (-2, 8) because x 8 = height and x =-2 is equn. of symmetry
So here we have
y = a(x - (-2))^2 + 8
y = a(x + 2)^2 + 8
Now at the point (-6, 2):
2 = a(-6+2)^2 + 8
2 = 16a + 8
16a = -6
1 = -3/8.
So our equation is y = 3/8(x + 2)^2 + 8
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Thanks,
<em>Deku ❤</em>