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3 years ago

The surface area is the amount a solid can hold. True False

2 answers:

7 0

This statement is false.

What you described is the volume of a solid. The surface area is the outermost layer of something or the outside part of it.

blsea [12.9K]3 years ago

6 0

The surface area is the amount a solid can hold is false.

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Which can be a next step in the construction of an angle with a side on line l that is congruent to ∠ABC?

iren2701 [21]

A) use a straightedge to draw a line thought D and F

6 0

3 years ago

Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z

Oliga [24]

Part a)

Given the expression

$54m^3n\:+\:81m^4n^2$

Apply exponent rule: $a^{b+c}=a^ba^c$

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn$ ∵ $m^4n^2=m^3mnn$

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

$=2\cdot \:27m^3n+3\cdot \:27m^3mnn$

Factor out the common term: 27m³n

$=27m^3n\left(2+3mn\right)$

Therefore,

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)$

Part B)

Given the expression

$15x^2y^3z+25x^3y^2z+35x^2y^2z$

Apply exponent rule: $a^{b+c}=a^ba^c$

$15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z$

Rewrite as

$=3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z$

Factor out common term 5y²x²z

$=5y^2x^2z\left(3y+5x+7\right)$

Therefore,

$15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)$

8 0

3 years ago

Whats the answer to #9 i need help fast!!

vekshin1

I got 784 inches cubed, I cut the figure into two, the first one was 8×4×14=448, the second was 8×3×14=336,
therefore 448+336=784

5 0

3 years ago

Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and

sergij07 [2.7K]

Answer:

a) sample size is 40

Step-by-step explanation:

(a)

$\sigma=4$ minutes

Margin of error, E is 75 seconds E=75/60= 1.25 minutes.

The level of significance $\alpha= 0.05$ for 95% level of significance

For 95% confidence interval $z_{\frac{\alpha}{2}}=1.96$ from standard deviation table

Sample size required, n

$n=\left (\frac{z_{\frac{\alpha}{2}}\cdot \sigma}{E} \right )^{2}=\left (\frac{1.96\cdot4}{75/60} \right )^{2}=39.337984$

Rounding off, n=40

Sample size =40

Keywords:

95% confidence, sample size, Wall Street Journal

3 0

3 years ago

(2, -4) and (6,-10) find the midpoint of the segment

asambeis [7]

The midpoint of the segment:
(4, 7)
x=4 y= -7

5 0

3 years ago