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3 years ago

Plz helppppp fastttttttt

Mathematics

1 answer:

Anna71 [15]3 years ago

4 0

Answer:

D resizing po

Step-by-step explanation:

i hope it help po

brainliest Po pls

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c(1)=−20 c(n)=c(n−1)+10 Find the 2nd term in the sequence.

Bad White [126]

Answer:

-10 is the second term.

Step-by-step explanation:

After the first term each term is obtained from the previous one by adding 10.

c(1) = -20

so c(2) = -20 + 10

= -10.

3 0

3 years ago

Consider the numbers √27 and √39.

kobusy [5.1K]

√27 = 5.2 (to 1 dp)
√39 = 6.2 (to 1 dp)
A. √39 is greater.
B. 6 is the only whole number between the two.
Hope this helped :)

3 0

3 years ago

4.80952380952 in fraction form

vladimir2022 [97]

Answer:

77/16

Step-by-step explanation:

8 0

2 years ago

8) through: (-3, -2), perp. to y = x – 1 A) y=-5x – 1 B) y=-4x – 5 C) y=-x – 5 D) y=-5x – 4

nexus9112 [7]

Answer:

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

Solution:

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1$

We know that, product of slopes of perpendicular lines is -1.

So, 1 $\times$ slope of perpendicular line = -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0

3 years ago

PLEASE HELP!! just look at the picture

arlik [135]

Answer:

its the math that solve

Step-by-step explanation:

4 0

3 years ago