What is the absolute value of -5+9

A model for the movement of a stock supposes that if the present price of the stock is s, then, after one period, it will be eit

aleksklad [387]

Answer:

$P(X\geq 470)=0.9991$

Step-by-step explanation:

Present price of stock is s, if x is the times that the stock increases (by u) among the 1000 periods we can calculate the price after 1000 periods as follows:

$s*u^n*d^{(1000-x)}$ note that if the price increase n periods, so it should decreases in the other 1000-x periods.

We need that the price be 30% higher or 1.3 times the initial price. That requirement is expressed as follows:

$s*u^n*d^{(1000-x)}>1.3s$

applying properties of exponents and reorganizing.

$d^{1000}(\frac{u}{d})^x>1.3$

solving for x

$1000 log(d)+ x log (\frac{u}{d})>log(1.3)$

$x >\frac{log(1.3)-1000 log(d)}{log (\frac{u}{d})}$

Using the values given d= 0.99 and u=1.012

$x > 469.208967$

So, we need at least 470 increase periods

Now we can calculate the probability of have 470 increase periods or more, taking into account that the distribution of x is binomial, the period can be and increase period with 0.52 of probability and we have 1000 total trials.

The formula for the binomial cumulative probability function is

$F(x;p,n) = \Sigma_0^x \left(\begin{array}{c}n&i\end{array}\right)p^i(1-p)^{n-i}$

With this formula we can calculate the probability of obtain x successful trials or less ( $P(X\leq x)$ ). There, p is the probability of success (probability of increase period in this case), x is the maximum number of successful trials, n the number of total trials. We should calculate F with x=470, p=0.52 and n= 1000. The result is $P(X\leq x)$ , but we need $P(X\geq x)$ so we can calculate that probability as

$P(X\geq x)=1-P(X\leq x)$

In order to calculate the cumulative function we can use excel function BINOM.DIST

BINOM.DIST(x,trials,probability,cumulative)

BINOM.DIST(470,1000,0.52,TRUE)

We obtain that $P(X\leq 470)=0.00087$ , so $P(X\geq 470)=1-0.00087=0.9991$

7 0

3 years ago

When Emily arrives from school she spent a minute eating a snack then she spent 15 playing with her dog and 32 doing her chores

Neporo4naja [7]

The question is incomplete:

When Emily arrived home from school she spent a minutes eating a snack. Then, she spent 15 minutes playing with her dog and 32 doing her chores . Finally, Emily spent 45 minutes finishing her homework. How long had Emily been home when she finished?

Answer:

Emily had been home for 1 hour and 33 minutes.

Step-by-step explanation:

In order to find the answer, first you have to add up the time she spent in each activity to find the amount of minutes she had been at home when she finished:

1+15+32+45=93

Now, you can express the 93 minutes in hours considering that one hour has 60 minutes. According to this, Emily had been home for 1 hour and 33 minutes (93-60=33).

8 0

3 years ago

Graph the follow in equation

AURORKA [14]

13 and 2 are numbers you could use in graph☺

8 0

3 years ago

Read 2 more answers

PLs i need help with this emergency

sasho [114]

Answer:

11, 15