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In-s [12.5K]
3 years ago
8

Pedestrian or bicycle $0.50

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
5 0
2 groups if 4 bicyclists or 4 groups of 2 bicyclists. Well it's only 1.75 per truck so since there were 4 trucks 4•1.75=7.00 :)
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X + y = -1<br> X - y = 7
enyata [817]
1: Solve for either x or y in one of the equations. So x + y = -1 is y = -x -1
2: substitute the new equation in the opposite equation. So x - (-x - 1) = 7
3: distribute the negative. X + x + 1 = 7
4: combine like terms. 2x + 1 = 7
5: solve for x. Subtract 1 on both sides. 2x = 6
6: divide by 2 to get x by itself. X = 3
7: plug the new value of x into one of the ORIGINAL equations. 3 + y = -1
8: solve for y. Subtract 3 on both sides.
Y = -4
9: the solution is written as (x,y) so the solution would be (3, -4)
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Find two integers whose sum is 3 and product is -108.
AleksandrR [38]

Answer:

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Step-by-step explanation:

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The value of 5s in 25,578
mash [69]

Answer:

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Step-by-step explanation:

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3 years ago
WILL MARK YOU BRAINLIEST !!!!
liq [111]

Answer:

\overline {PM} \cong \overline {ON} because they are opposite sides of a parallelogram.

Step-by-step explanation:

First of all, let us have a look at the definition of a parallelogram.

<em>A parallelogram is a closed 4 sided figure (i.e. a quadrilateral) made up with two pairs of straight lines such that the two pairs are parallel and equal to each other.</em>

<em></em>

For example, let us consider a quadrilateral ABCD as attached in the diagram in answer area.

The two pair of lines are:

AB,  DC and BC, AD

For ABCD to be a parallelogram, the lines

AB and DC must be parallel to each other and AB = DC

AND

BC and AD must be parallel to each other and BC = DA

------------------------------

In the given question, we are given that the quadrilateral MNOP is a parallelogram.

The two pairs opposite lines are OP, NM and PM, ON.

As per the definition of a parallelogram,

OP and NM must be <em>parallel and equal </em>to each other.

AND

PM and ON must be <em>parallel and equal </em>to each other.

\therefore \overline {PM} \cong \overline {ON}.

Hence proved.

6 0
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