Hello,
Let's assume h the heigth of the parallelogram
h/6=sin 60°==>h=√3/2*6=3√3
Area=3√3 * 12=36√3
Where is q? What should i do?
Answer:
ok so this problem you are basically just rearranging it. you're going to want y by itself.
Step-by-step explanation:
let's start with the original equation: 5-y=1/3x +12
so first you have to move the five over, so you subtract 5 from both sides. -y=1/3x+12-5
then you subtract the 5 from the twelve since they're like terms: -y=1/3x+7
and finally you have to move the negative over. when you move the negative think of it like dividing negative one from both sides, everything on the other side has to get the negative.
so we're left with y=-1/3x-7
I hope this helps!
Hello!!
Total = 3/7 + 4/5 + 2/3
= 0.428571429 + 0.8 + 0.66666667
= 199/105
= 1.89524.....
≈ 1.90 (rounded to two decimal places)
Good luck :)