Finding first six terms of a sequence
2 answers:
To find the first six terms of a sequence, you first of all need to have a starting number. You will also need to have a pattern depending on the kind of sequence
For example, if our first number is 1 and our pattern is that we raise each of the natural numbers to the power of 2, we can now derive our sequence. To get the sequence, you've gotta carry out that pattern on each umber to be used. Since we are looking for the first six terms, the operation will only be carried out on 1,2,3,4,5 and 6. In the end this will give us;
and 
=
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For example, if our first number is 1 and our pattern is that we raise each of the natural numbers to the power of 2, we can now derive our sequence. To get the sequence, you've gotta carry out that pattern on each umber to be used. Since we are looking for the first six terms, the operation will only be carried out on 1,2,3,4,5 and 6. In the end this will give us;
Please mark me as brainliest.
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Answer:
(1) 0.5933
(2) 0.8955
Step-by-step explanation:
We are given that all bags entering a research facility are screened.
Let Probability that bags entering the building contains forbidden material,
P(F) = 0.69
Probability that bags entering the building does not contains forbidden material, P(NF) = 1 - 0.69 = 0.31
Let event A = alarm gets triggered
Probability that alarm gets trigger given the bags contain forbidden material, P(A/F) = 0.77
Probability that alarm gets trigger given the bags does not contain forbidden material, P(A/NF) = 0.20
(1) Probability that a bag triggers the alarm, P(A) ;
P(A) = P(F) * P(A/F) + P(NF) * P(A/NF)
= (0.69 * 0.77) + (0.31 * 0.20) = 0.5313 + 0.062
= 0.5933
Therefore, probability that a bag triggers the alarm is 0.5933 .
(2) Probability that a bag that triggers the alarm will actually contain forbidden material is given by P(F/A) ;
Using Bayes' Theorem;
P(F/A) = =
=
= 0.8955