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elixir [45]
3 years ago
8

Finding first six terms of a sequence

Mathematics
2 answers:
Jlenok [28]3 years ago
6 0
2, 4, 6, 8, 10, 12


difference is 2
motikmotik3 years ago
5 0
To find the first six terms of a sequence, you first of all need to have a starting number. You will  also need to have a pattern depending on the kind of sequence
For example, if our first number is 1 and our pattern  is that we raise each  of the natural numbers to the power of 2, we can now derive our sequence. To get the sequence, you've gotta carry out that pattern on each umber to be used. Since we are looking for the first six terms, the operation will only be carried out on 1,2,3,4,5 and 6. In the end this will give us;
1^2, 2^2, 3^2, 4^2, 5^2 and 6^2=1, 4, 9, 16, 25, 36
Please mark me as brainliest.
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Is is square root of 1.6875 a rational number
mamaluj [8]

<em><u>Question:</u></em>

Is square root of 1.6875 a rational number ?

<em><u>Answer:</u></em>

Square root of 1.6875 a rational number is not a rational number

<em><u>Solution:</u></em>

Given that we have to find square root of 1.6875 and determine if it is rational number or not

Let us first find square root of 1.6875

\sqrt{1.6875} = 1.29903810568

Let us understand about rational number

A rational number is a number that can be expressed as a fraction (ratio) in the form \frac{p}{q} where p and q are integers and q is not zero.

When a rational number fraction is divided to form a decimal value,  it becomes a terminating or repeating decimal.

So the number 1.29903810568 is not a rational number

<em><u>In other words we can say,</u></em>

Only the square roots of square numbers are rational. Here 1.6875 is not a perfect square. So it is not rational number

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Answer:

t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322

Step-by-step explanation:

We have a sample of size n = 35, \bar{x} = 92 and s = 5. As we want to construct a 95% confidence interval to estimate the value of the true population mean \mu, we should use the pivotal quantity given by T = \frac{\bar{X}-\mu}{S/\sqrt{n}} which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322, i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that P(-2.0322\leq T\leq 2.0322) = 0.95 because of the simmetry of the t distribution.

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