An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
15/7
5/2
2.54
2.7
That’s the order from least to greatest
True, because they make up the two line segments make up the right angle
Answer:
2/3
Step-by-step explanation:
Let's define z = x-y, so solving for z will tell us exactly what we want to know. Then we can substitute for x: x = z+y, and our equations become ...
7(z+y)+3y = 8 ⇒ 7z +10y = 8
6(z+y)-3y = 5 ⇒ 6z +3y = 5
We can eliminate the y-variable by subtracting 3 times the first equation from 10 times the second:
10(6z +3y) -3(7z +10y) = 10(5) -3(8)
60z +30y -21z -30y = 50 -24 . . . . eliminate parentheses
39z = 26 . . . . collect terms
z = 26/39 = 2/3 . . . . . divide by the coefficient of z and reduce
The value of x - y is 2/3.
_____
The attached graph shows (x, y) = (1, 1/3), so x - y = 1 - 1/3 = 2/3.
Answer:
x > -3
Step-by-step explanation:
–3x + 6 < 15
Subtract 6 from each side
–3x + 6-6 < 15-6
-3x < 9
Divide each side by -3, remembering to flip the inequality
-3x/-3 > 9/-3
x > -3