The manager of a health food store sells peanuts for $8 a pound and premium cashews for $13 a pound. If he wishes to make a 400
2 answers:
Answer: 80 pounds
Step-by-step explanation:
Let x be the amount of cashews needed to make a 400 pound cashew and peanut mix.
Then the amount of peanuts= 400-x
Now, the price of cashews before mix = 13x
the price of peanuts before mix = 8(400-x)
the price of 400 pound mix = $9(400)=$3600
According to the question:
Hence, he use 80 pounds of cashews .
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Answer:
0.1% probability that the average score of a random sample of 20 students exceeds 59.5.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that the average score of a random sample of 20 students exceeds 59.5?
This is 1 subtracted by the pvalue of Z when . So
has a pvalue of 0.9990.
So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.