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kari74 [83]
3 years ago
13

Graph the solution set to this inequality. 3x - 11 > 7x + 9

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

x<-5                       <--------o open circle

Step-by-step explanation:

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Write two equations. the first equation should express the area of the square (a as a function of the length (l of a side. the s
Sergeu [11.5K]

Answer:

a = l²

v = s³

Step-by-step explanation:

The area of a rectangle is the product of its length and width. When that rectangle is a square, the length and width are the same. Here, they are given as "l". Then the area of the square is ...

a = l·l = l²

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The volume of a cuboid is the product of its height and the area of its base. A cube of edge length s has a square base of side length s and a height of s. Then its volume will be ...

v = s·(s²) = s³

The two equations you want are ...

• a = l²

• v = s³

6 0
3 years ago
James says that 12 is a common factor of 3 and 4.june says that 12 is common multiple of 3 and 4.who is correct.
Sliva [168]
June is correct because <span>12 is a </span>multiple<span> of both </span>3 and 4<span>.</span>
7 0
3 years ago
Read 2 more answers
HI PEEPS CAN ANYONE PLS PAY ATTENTION TO MY Q'S FOR ONCE :'(
leonid [27]
Square root of 154m^2 = 12.5~
So adding 1.5 to 12.5 and subtracting 1.5 to 12.5 gives us 11 and 14
Your dimensions are 11x14
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5 0
4 years ago
7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t
Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

\frac{x^a}{x^b}=x^{a-b}

x^0=1

(x^a)(x^b)=x^{a+b}

x^{-a}=\frac{1}{x^a}


\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=

\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=

\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=

(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=

(7^{-5-(-5)})(2^{0-3})=

(7^0)(2^{-3})=

\frac{1}{2^3}=

\frac{1}{8}

7 0
3 years ago
If the square root of 61 is the longest side length in the triangle and the shorter sides are x and x+1, find the value of x tha
Tju [1.3M]

Answer:

  x = 5

Step-by-step explanation:

You want to find x such that ...

  x^2 +(x +1)^2 = 61

  2x^2 +2x -60 = 0 . . . . . simplify, subtract 61

  x^2 +x -30 = 0 . . . . . . . divide by 2

  (x +6)(x -5) = 0 . . . . . . . . factor; solutions will make the factors be zero.

The relevant solution is x = 5.

5 0
3 years ago
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