he can either send one half or the other half.
Answer:
Option C) There are enough evidence that at significance level of 0.05 to support the claim that the the population mean market value of houses in the neighborhood where she works is greater than $250,000.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = $250,000
Sample mean,
= $259,860
Sample size, n = 35
Alpha, α = 0.05
Sample standard deviation, σ = $24.922
First, we design the null and the alternate hypothesis
We use One-tailed t test to perform this hypothesis.
Formula:

Since the p-value is less than the significance level, we fail to accept the null hypothesis.
There are enough evidence that at significance level of 0.05 to support the claim that the the population mean market value of houses in the neighborhood where she works is greater than $250,000.
x = 11.2 this is rounded to the nearest tenth :)
Answer:
5 boxes of diaries
6 boxes of pencils
10 boxes of rulers
Step-by-step explanation:
In order to find the smallest number of units that would be possible to buy, find the least common multiple between the number of units in each box:

The number of boxes required for each item to get 60 units is:

the smallest number of boxes of each item he could buy is:
5 boxes of diaries
6 boxes of pencils
10 boxes of rulers
Answer:
−9⋅(5j+k) = -45j -9k.
Step-by-step explanation:
Given : −9⋅(5j+k)
To find : distributive property.
Solution : −9⋅(5j+k)
By distributive property a( b +c ) = a*b + a*c.
Then −9⋅(5j+k) = -9 *5j + (-9 *k)
−9⋅(5j+k) = -45j -9k.
Therefore, −9⋅(5j+k) = -45j -9k.