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PolarNik [594]
3 years ago
10

Consider the following two ordered bases of R2 R2: BC=={⟨1,2⟩,⟨3,5⟩},{⟨−1,1⟩,⟨1,−2⟩}. B={⟨1,2⟩,⟨3,5⟩},C={⟨−1,1⟩,⟨1,−2⟩}. Find th

e change of basis matrix from the basis BB to the basis CC. [id]CB=[id]BC= ⎡⎣⎢⎢[ ⎤⎦⎥⎥] Find the change of basis matrix from the basis CC to the basis BB. [id]BC=
Mathematics
1 answer:
Tamiku [17]3 years ago
7 0

Answer:

This question is maybe r2+ =>()0?

Step-by-step explanation:

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There are 8 people on the debate team. In how many ways can the coach choose 4 members to send to competition?
meriva

he can either send one half or the other half.

4 0
3 years ago
Read 2 more answers
Rebecca is a real estate agent who would like to find evidence supporting the claim that the population mean market value of hou
nydimaria [60]

Answer:

Option C) There are enough evidence that at significance level of 0.05 to support the claim that the the population mean market value of houses in the neighborhood where she works is greater than $250,000.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = $250,000

Sample mean, \bar{x} = $259,860

Sample size, n = 35

Alpha, α = 0.05

Sample standard deviation, σ = $24.922

First, we design the null and the alternate hypothesis

H_{0}: \mu = 250,000\text{ dollars}\\H_A: \mu > 250,000\text{ dollars}

We use One-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} } = 2.34

0.01 < \text{ p-value }< 0.025

Since the p-value is less than the significance level, we fail to accept the null hypothesis.

There are enough evidence that at significance level of 0.05 to support the claim that the the population mean market value of houses in the neighborhood where she works is greater than $250,000.

6 0
3 years ago
Please solve!!!! Solve for x to the nearest tenth.
ki77a [65]

x = 11.2 this is rounded to the nearest tenth :)

6 0
3 years ago
Q1.
Alinara [238K]

Answer:

5 boxes of diaries

6 boxes of pencils

10 boxes of rulers

Step-by-step explanation:

In order to find the smallest number of units that would be possible to buy, find the least common multiple between the number of units in each box:

12\ \ 10\ \ 6\ |2\\6\ \ \ \ 5\ \ \ 3\ |2\\3\ \ \ \ 5\ \ \ 3\ |3\\1\ \ \ \ 5\ \ \ 1\ |5\\1\ \ \ \ 1\ \ \ 1\ | = 2*2*3*5=60

The number of boxes required for each item to get 60 units is:

d=\frac{60}{12} = 5\ boxes \\p=\frac{60}{10} = 6\ boxes \\r=\frac{60}{6} = 10\ boxes

the smallest number of boxes of each item he could buy is:

5 boxes of diaries

6 boxes of pencils

10 boxes of rulers

8 0
3 years ago
−9⋅(5j+k) do distrubutibr property
Serjik [45]

Answer:

−9⋅(5j+k) =  -45j -9k.

Step-by-step explanation:

Given  : −9⋅(5j+k)

To find : distributive property.

Solution : −9⋅(5j+k)

By distributive property a( b +c ) = a*b + a*c.

Then  −9⋅(5j+k) =  -9 *5j + (-9 *k)

−9⋅(5j+k) =  -45j -9k.

Therefore, −9⋅(5j+k) =  -45j -9k.

3 0
3 years ago
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