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Gnesinka [82]
3 years ago
11

Three subtracted from the product of

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0
5w-3 > -29
Add 3 at both sides

5w > -26
Divide 5 at both sides

w > -26/5

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Find the product of the sum of 57 and 16 and the difference of 61 and 31​
Sergio039 [100]

Step-by-step explanation:

???

what is the problem ? you don't know how to add, subtract or multiply yet ?

sum of 57 and 16 : 57 + 16 = 73

difference of 61 and 31 : 61 - 31 = 30

the product of the sum and the difference :

73 × 30 = 2190

3 0
2 years ago
Please help I need to know the answer
Kazeer [188]
Answer:

Original price: 51$
Discount percentage: 40%

-----------

Details
Discount = Original Price x Discount %/100
Discount = 51 × 40/100
Discount = 51 x 0.4
You save = $20.40

Final Price = Original Price - Discount
Final Price = 51 - 20.4
Final Price = $30.60

there you go, coupon A is 20.40$ Dollars less than the price of coupon B, your welcome :)) i wish u best of luck in the exam:)

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4 0
3 years ago
BC = 6x + 6,<br> AB = 8 +9, and<br> AC = 141.<br> Find BC
Dahasolnce [82]

Answer: 60

Step-by-step explanation:

Since AB and BC creates AC, we can add them together to find x, then use that to find the value of BC.

8x+9+6x+6=141                  [combine like terms]

14x+15=141                          [subtract both sides by 15]

14x=126                               [divide both sides by 14]

x=9

Now that we have found the value of x, we can plug that into BC.

6(9)+6                                 [multiply]

54+6                                   [add]

60

Now, we know the length of BC is 60.

3 0
3 years ago
Stern MASS ASB is doing a Valentine’s Day Fundraiser. They are selling roses for $3 each and carnations for $2 each.They sold a
horrorfan [7]

Answer:

They sold

20 Roses and 20 Carnations

Step-by-step explanation:

The total sales of 40 flowers is $100 not $10 as in the question

Roses=$3

Carnations=$2

Total flowers sold=40

Total sales=$10

Let Roses=r

Carnations=c

c+r=40. (1)

3r+2c=100 (2)

From (1)

c=40-r

Substitute c=40-r into (2)

3r+2c=100

3r+2(40-r)=100

3r+80-2r=10

r=100-80

r=20

Substitute r=20 into (1)

c+r=40

c+20=40

c=40-20

=20

c=20

r=20

Check:

3r+2c=100

3(20)+2(20)=100

60+40=100

100=100

4 0
3 years ago
How many pentagons can be drawn by joining the vertices of a polygon with 10 sides?
inn [45]
..............10c5..............
5 0
3 years ago
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