How do I solve using law of sines or law of Cosines ?

Mathematics

1 answer:

n200080 [17]3 years ago

5 0

If you want to solve this problem using law of sin. Then use a/sinA = b/sinB = c/sinC.

if you want to solve this problem using law of cos. Then use a² = b² + c² - 2bc cosA, b² = a² + c² - 2ac cosB, c² = a² + b² - 2ac cosC

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zalisa [80]

The confidence interval formula is computed by:

Xbar ± Z s/ sqrt (n)

Where:

Xbar is the mean

Z is the z value

S is the standard deviation

N is the number of samples

So our given are:

90% confidence interval with a z value of 1.645

Sample size 40, 45

Mean 180, 179

Standard deviation 2, 4

So plugging that information in the data will give us a confidence interval:

For 1:

Xbar ± Z s/ sqrt (n)

= 180 ± 1.645 (2 / sqrt (40))

= 180 ± 1.645 (0.316227766)

= 180 ± 0.520194675

= 179.48, 180.52

For 2:

Xbar ± Z s/ sqrt (n)

= 179 ± 1.645 (4 / sqrt (45))

therefore, the answer is letter b

8 0

4 years ago

Apply the distributive property to create an equivalent expression 1/3(3j+6) what the answer

Anna71 [15]

Answer:

$\large\boxed{\dfrac{1}{3}(3j+6)=j+2}$

Step-by-step explanation:

The distributive property: <em>a(b + c) = ab + ac</em>.

$\dfrac{1}{3}(3j+6)=\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)(3\!\!\!\!\diagup^1j)+\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)(6\!\!\!\!\diagup^2)=1j+(1)(2)=j+2$