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Mice21 [21]
3 years ago
7

What’s is the difference between an improper fraction and mixed number

Mathematics
1 answer:
Darya [45]3 years ago
6 0

Answer:

An improper fraction is always 1 or greater than 1. And, finally, a mixed number is a combination of a wholenumber and a proper fraction.In a proper fraction, the numerator is always less than the denominator. Examples ofproper fractions include and 

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Help please!!! Find x and Y
Sav [38]

Answer:

x = 40

y = 15

Step-by-step explanation:

Given is an equilateral triangle.

Measure of each angle of an equilateral triangle is 60°.

Therefore,

(x + 20)° = 60°

x + 20 = 60

x = 60 - 20

x = 40

4y = 60

y = 60/4

y = 15

8 0
3 years ago
Can someone show me the steps to solving this?!?!!
Gala2k [10]

Answer:

la raíz cuadrada entre 3

6 0
3 years ago
Does this graph represent a function? What is the domain and range of the graph
Daniel [21]
Yes it is a function. It passes the vertical line test. In other words, it is impossible to draw a single vertical line through more than one point on the V shaped graph. Any input leads to exactly one output.

The domain is the set of all real numbers. This is because we can plug in any x value leading to some specific y value. There are no holes or gaps or jumps to indicate we must restrict any given x value. The domain would not be the set of whole numbers only because values between the whole numbers (eg: decimal values like x = 2.75) work just fine. 

The range is the set of y values such that y is either 0 or larger than 0. In short, the range is y \ge 0. Notice how any point on the V shaped graph has a y coordinate that is either 0 or larger than 0. It is impossible to get a y value that is negative.

--------------------------------------------------------------------

In summary,
Yes it is a function
Domain: all real numbers
Range: y \ge 0
So the answer is choice B
6 0
3 years ago
F(x) = 4√(2x³-1)<br> F'(x) =.....?
goldfiish [28.3K]

Answer:

\large\boxed{f'(x)=\dfrac{12x^2}{\sqrt{2x^3-1}}}

Step-by-step explanation:

f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}

6 0
3 years ago
Josh is clumsy and often drops his
marusya05 [52]
It is definitely worth it for Josh to purchase a warranty. If he buys something and then breaks it within the amount of time the warranty covers, then he would be able to get a new one.
5 0
2 years ago
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