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lions [1.4K]
3 years ago
14

(125) - ( ) = -100

Mathematics
2 answers:
Delvig [45]3 years ago
8 0
1. 225
2. 100
3. -50
4. 15
Ray Of Light [21]3 years ago
6 0
225 100 -50 15 !!!!!

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How to solve this problem
RSB [31]
Holy @$#% THAT LOOKS HARD! Sorry, I can't help I don't know that math yet. 
5 0
4 years ago
A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u
OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

\displaystyle\frac{8000\pi\sqrt{2}}{3}

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

x^2+y^2=15^2\to y=\sqrt{225-x^2}

Then we set the integral for the volume by using shell method:

\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx

That can be solved by substitution:

u=225-x^2\to du=-2xdx

The limits of integration also change:

For x=5: u=225-5^2=200

For x=15: u=225-15^2=0

So the integral becomes:

\displaystyle -\int_{200}^{0}\pi \sqrt{u}du

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

\displaystyle \int_{0}^{200}\pi u^{1/2}du

Then applying the basic rule we get:

\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}

Since that is just half of the solid, we multiply by 2 to get the complete volume:

\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}

=\displaystyle\frac{8000\pi\sqrt{2}}{3}

5 0
4 years ago
Use vieta's theorem to solve the problems.
Mnenie [13.5K]

Using Vieta's Theorem, it is found that c = 72.

<h3>What is the Vieta Theorem?</h3>
  • Suppose we have a quadratic equation, in the following format:

y = ax^2 + bx + c

  • The roots are p and q.

The Theorem states that:

p + q = -\frac{b}{a}

pq = \frac{c}{a}

In this problem, the polynomial is:

x^2 - 17x + c

Hence the coefficients are a = 1, b = -17.

Since the difference of the solutions is 1, we have that:

p - q = 1

p = 1 + q

Then, from the first equation of the Theorem:

p + q = -\frac{b}{a}

1 + q + q = 17

2q = 16

q = 8

p = 1 + q = 9

Now, from the second equation:

pq = \frac{c}{a}

72 = c

c = 72

To learn more about Vieta's Theorem, you can take a look at brainly.com/question/23509978

6 0
2 years ago
If a wall is in a 1/4 in scale drawing is 6 in tall how tall is the actual wall
vekshin1
So 1/4
that measn that the scale wall is 6 inches while the real wall is 4 times 6=24 inches tall (logically, it would be something like 1in/4ft so it woul dbe 24 feet not 24 inches but ok)

so 1/4
6 inches scale drawing is 1/4 of real wall
6=1/4 real
multiply by 4
24=real

asnwer is 24 inches
6 0
3 years ago
An amusement park offers two options. Option 1 involves a $10 admission fee plus $0.50 per ride. Option 2 involves a $6 admissio
Art [367]

Answer:

16 rides

Step-by-step explanation:

Option 1 . Admission fee = $10

                Each ride = $0.50

Option 2 . Admission fee = $6

                Each ride = $0.75

Let no. of rides be x

So, cost of ride according to option 1 = 0.50x

So, total cost after having x rides according to option 1 :

= 10+0.50x  ---1

Cost of ride according to option 2 = 0.75x  

So, total cost after having x rides according to option 2 :

= 6+0.75x  --2

Now to find the beak even point i.e. having the same cost

Equate 1 and 2

10+0.50x=6+ 0.75x

10-6= 0.75x-0.50x

4= 0.25x

\frac{4}{0.25} =x

16=x

Thus for 16 rides , the two options have the same cost .

Hence the break even point is 16 rides

5 0
4 years ago
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