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3 years ago

PLEASE HELP!!!!!!! I NEED HELP!!!!!!!!!!

Mathematics

1 answer:

miss Akunina [59]3 years ago

7 0

Answer:

342in

Step-by-step explanation:

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A lawn in the shape of a trapezoid has an area of 1,833 square meters. The length of the other base is 42 meters. What is the he

Klio2033 [76]

The area of a trapezoid can be found with this formula:

$A=\frac{1}2(b_1+b_2)h$

Where b1 and b2 are the bases and h is the height.

If we plug in what we know we can solve for the height.
We know that b1 = 52, b2 = 42, and A = 1833. Let's solve.

$1833=\frac{1}2(52+42)h\\1833=\frac{1}2\times94h\\1833=47h\\\boxed{h=39\ m}$

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3 years ago

Y varies inversely as x, and y = 50 when x = 10. What is the value ofy when x = 20?<br> 100

Mrrafil [7]

Answer:

Step-by-step explanation:

Since y varies inversely with x, the relation between y and x will be:

$y \propto \frac{1}{x}$

Introducing the proportionality constant, we can write:

$y = \frac{k}{x}$

Using the first set of given values of x and y, we get:

$50=\frac{k}{10}\\\\k = 500$

This means, the relation between y and x is:

$y = \frac{500}{x}$

We have to find y if x = 20. Using this value in above equation, we get:

$y=\frac{500}{20} \\\\ y = 25$

Thus y would be 25 if x is 20.

8 0

3 years ago

Previous 20 Two groups leave on different flights from the same airport. Group A flies 200 miles due south, then turns 68° towar

Oksana_A [137]

Answer:

Group B is farther from the airport.

Step-by-step explanation:

To find the distance of each group to the airport we can use the law of cosines in the triangle created with the two movements done and the resulting total distance.

Law of cosines:

$c^2 = a^2 + b^2 - 2ab*cos(angle)$

For group A, we have the sides of 200 miles and 75 miles, and the angle between the sides is (180-68) = 112°, so the third side of the triangle is:

$c^2 = 200^2 + 75^2 -2*200*75*cos(112)$

$c^2 = 56863.198$

$c = 238.46\ miles$

For group B, we also have the sides of 200 miles and 75 miles, and the angle between the sides is (180-51) = 129°, so the third side of the triangle is:

$c^2 = 200^2 + 75^2 -2*200*75*cos(129)$