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4 years ago

5

9a-ab+5b if a=2 and b=7

2 answers:

stira [4]4 years ago

8 0

9×2-2×7+5×7=18-14+35=39

schepotkina [342]4 years ago

6 0

$Solution, 9\left(2\right)-\left(2\right)\left(7\right)+5\left(7\right)=39$

$Steps:$

$9\left(2\right)-\left(2\right)\left(7\right)+5\left(7\right)$

$Follow\:the\:PEMDAS\:order\:of\:operations$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:9\left(2\right),\\9\left(2\right)=18,\\18-\left(2\right)\left(7\right)+5\left(7\right)$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:\left(2\right)\left(7\right),\\\left(2\right)\left(7\right)=14,\\18-14+5\left(7\right)$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:5\left(7\right),\\5\left(7\right)=35,\\18-14+35$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:18-14+35,\\18-14=4,\\4+35,\\4+35=39,\\$

$\mathrm{The\:Correct\:Answer\:is\:39}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

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What's an equation that the passes through (-6,4) and is parallel to y=1/2x+8

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Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:

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3 years ago

line a passes through the points(-4,-6) and (2,12) Library passes through the points (6,0) and (-4,20) find the point where line

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Step-by-step explanation:

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3 years ago

A bag of marbles consists of 14 blue marbles and 7 red marbles. If you reach into the bag and choose 2 marbles,

julsineya [31]

Answer:

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Step-by-step explanation:

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3 years ago

In triangle ABC, a = 3, b = 5, and c = 7. Find the approximate value of angle A.

Lady bird [3.3K]

Answer:

21.8° (22° to the nearest degree)

Step-by-step explanation:

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6 0

3 years ago

g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

3 years ago