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3 years ago

The quotient of a number and five

Mathematics

1 answer:

Gala2k [10]3 years ago

4 0

Answer:

$\frac{x}{5}$

Step-by-step explanation:

The number is unknown so you just put in x and write it over 5.

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The composite figure below is a triangle and a semicircle. What is the exact area of the figure? Do NOT round at any point!

Tatiana [17]

(2,3) and (-1,-5)
Distance =√(-1-2)^2 +(-5-3)^2
Distance =√73 (diamter)
radius = (√73) / 2

area of semi-circle:
= 1/2 πr^2
= 1/2 π ((√73) / 2)^2
= 73 π / 8
= 9.125 π

area of triangle:
= 1/2 (8)(3)
= 12

Area of the figure = area of semi-circle + area of triangle<span>

</span>= 9.125π + 12

answer
9.125π + 12

3 0

4 years ago

( 1 + 1 ) + ( 1 + 1 + 1) in standard form

Simora [160]

Answer:

if im correct the answer should be 5 x 10

Step-by-step explanation:

6 0

2 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.

xz_007 [3.2K]

Answer:

Part 1) $f(x)=\frac{2x-1}{x+2}$ -------> $f^{-1}(x)=\frac{-2x-1}{x-2}$

Part 2) $f(x)=\frac{x-1}{2x+1}$ -------> $f^{-1}(x)=\frac{-x-1}{2x-1}$

Part 3) $f(x)=\frac{2x+1}{2x-1}$ -----> $f^{-1}(x)=\frac{x+1}{2(x-1)}$

Part 4) $f(x)=\frac{x+2}{-2x+1}$ ----> $f^{-1}(x)=\frac{x-2}{2x+1}$

Part 5) $f(x)=\frac{x+2}{x-1}$ -------> $f^{-1}(x)=\frac{x+2}{x-1}$

Step-by-step explanation:

Part 1) we have

$f(x)=\frac{2x-1}{x+2}$

Find the inverse

Let

y=f(x)

$y=\frac{2x-1}{x+2}$

Exchange the variables x for y and t for x

$x=\frac{2y-1}{y+2}$

Isolate the variable y

$x=\frac{2y-1}{y+2}\\ \\ xy+2x=2y-1\\ \\xy-2y=-2x-1\\ \\y[x-2]=-2x-1\\ \\y=\frac{-2x-1}{x-2}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{-2x-1}{x-2}$

Part 2) we have

$f(x)=\frac{x-1}{2x+1}$

Find the inverse

Let

y=f(x)

$y=\frac{x-1}{2x+1}$

Exchange the variables x for y and t for x

$x=\frac{y-1}{2y+1}$

Isolate the variable y

$x=\frac{y-1}{2y+1}\\ \\2xy+x=y-1\\ \\2xy-y=-x-1\\ \\y[2x-1]=-x-1\\ \\y=\frac{-x-1}{2x-1}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{-x-1}{2x-1}$

Part 3) we have

$f(x)=\frac{2x+1}{2x-1}$

Find the inverse

Let

y=f(x)

$y=\frac{2x+1}{2x-1}$

Exchange the variables x for y and t for x

$x=\frac{2y+1}{2y-1}$

Isolate the variable y

$x=\frac{2y+1}{2y-1}\\ \\2xy-x=2y+1\\ \\2xy-2y=x+1\\ \\y[2x-2]=x+1\\ \\y=\frac{x+1}{2(x-1)}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{x+1}{2(x-1)}$

Part 4) we have

$f(x)=\frac{x+2}{-2x+1}$

Find the inverse

Let

y=f(x)

$y=\frac{x+2}{-2x+1}$

Exchange the variables x for y and t for x

$x=\frac{y+2}{-2y+1}$

Isolate the variable y

$x=\frac{y+2}{-2y+1}\\ \\-2xy+x=y+2\\ \\-2xy-y=-x+2\\ \\y[-2x-1]=-x+2\\ \\y=\frac{-x+2}{-2x-1} \\ \\y=\frac{x-2}{2x+1}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{x-2}{2x+1}$

Part 5) we have

$f(x)=\frac{x+2}{x-1}$

Find the inverse

Let

y=f(x)

$y=\frac{x+2}{x-1}$

Exchange the variables x for y and t for x

$x=\frac{y+2}{y-1}$

Isolate the variable y

$x=\frac{y+2}{y-1}\\ \\xy-x=y+2\\ \\xy-y=x+2\\ \\y[x-1]=x+2\\ \\y=\frac{x+2}{x-1}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\frac{x+2}{x-1}$

7 0

3 years ago

Help me asap!!! Please!!!

choli [55]

Answer:

4) 33.51 cu.in

5) 84.82 cu.m

7) 2.09 cu.ft

8) 1047.197 cu.cm (CC)

11) 163.62 cu.in

Step-by-step explanation:

Volume is h/3x πr^3

4) 4/3 x π x 2^3 = 33.51

5) 3/3 x π x 3^3 = 84.82

7) 2/3 x π x 1^3 = 2.09

8) 8/3 x π x 5^3 = 1047.197

11) 10/3 x π x 2.5^3 = 163.62

4 0

3 years ago

If the vertex of a parabola is (-4,-7), what is the axis of symmetry?

mel-nik [20]

Answer:

-4

Step-by-step explanation:

Given vertex, the axis of symmetry is x = h.

4 0

2 years ago