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2 years ago

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Match the task to the occupation.

1 answer:

bekas [8.4K]2 years ago

3 0

According to the information, occupations and functions are organized as follows: music editor - blends music to components of a film, sound mixer - makes recording during program production, and recording engineer - maintains and operates recording equipment.

<h3>What is an occupation?</h3>

Occupation is a term that comes from the Latin <em>occupatio</em>, which is linked to the verb to occupy (to appropriate something, reside in a home, arouse someone's interest). The concept is used as a synonym for work or labor.

According to the above, the functions and occupations that best match are:

Music editor - blends music to components of a film
Sound mixer - makes recording during program production.
Recording engineer - maintains and operates recording equipment.

Learn more about occupations in: brainly.com/question/20199800

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N+5 - n-10=1 The n=5 and n-10 are in square root symbols

patriot [66]

$D:x\geq-5 \wedge x\geq10\\
D:x\geq10\\\\
\sqrt{n+5}-\sqrt{n-10}=1\\
\sqrt{n+5}=1+\sqrt{n-10}\\
n+5=1+2\sqrt{n-10}+n-10\\
2\sqrt{n-10}=14\\
\sqrt{n-10}=7\\
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2 years ago

2 (X+3) <br> What is x ?<br><br> PLS HELP ASAP

anastassius [24]

Step-by-step explanation:

2(x＋3)

2x＋6

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3 years ago

Read 2 more answers

Euguene sold half his books and then bought 17 more he now has 30

FromTheMoon [43]

Answer:

E started with 26 books, sold 13 books, bought 17 more books, and ended with 30 books

Step-by-step explanation:

E has _ books: x

E Sells 1/2 of that _ books: x/2

E buys 17 books and now had 30: (x/2) + 17 = 30

30 - 17 = 13

13 x 2 = 26

x/2 = 26

13 + 17 = 30 <-- checking work

My guess is that x = 13

You didn't clarify what exactly you are looking for but I hope this helps clarify some steps of the problem anyway!

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2 years ago

The formula I = PRT where I = Interest, P = principal, R = rate, and T = time is used to calculate the amount of simple interest

Marta_Voda [28]

Answer:

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3 years ago

How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide

kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

$CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

$MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}$

$=[\frac{1.96\times 60}{2}]^{2}$

$=3457.44\\\approx 3458$

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

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2 years ago