Number 4 and 6 are correct because you can only add variables with other variables so that is why 4 and 6 are correct
6 goes in to 906 151 times
Answer:
<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>
Step-by-step explanation:
In triangle DEF, we have:
<u>Given</u>:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
<u>Proof</u>: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)
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Answer:
(x, y) = (1, 3)
Step-by-step explanation:
given the 2 equations
x + y = 4 → (1)
y = 3x → (2)
Substitute y = 3x into (1)
x + 3x = 4
4x = 4 ( divide both sides by 4 )
x = 1
Substitute x = 1 into (2) for corresponding value of y
y = 3 × 1 = 3
solution is (1, 3 )
Answer:
3 (5) x x x x y z z all numbers are prime and all exponents are 1.
Step-by-step explanation: