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klasskru [66]
2 years ago
6

Find the value of x. I WILL GIVE 100 POINTS ANSWER QUICK!

Mathematics
2 answers:
Liula [17]2 years ago
6 0

Answer:0.714 not sure exactly  if i need to simplify, mullitiply,  or divide.

Step-by-step explanation:

Nana76 [90]2 years ago
5 0
The answer is 0.714 ! hope this helped clarify
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If a < 0 and c > b, circle the expression that is greater:
matrenka [14]

Answer:

The expression that is greater is a (b - c)

Step-by-step explanation:

  • a < 0 and c > b, this means <u>(by the addition property)</u> that c - c > b - c⇒0 > b - c

so for the product <u>a(b - c) </u>we would have a multiplication of a negative number <em>a</em> and another negative number <em>(b - c)</em>. We know that the result of the <u>multiplication of two negative numbers  is a positive number.</u>

Therefore, a (b - c) > 0

  • a < 0 and c > b, this means <u>by the addition property</u> that c - b > b - b⇒ c - b > 0

so for <u>a(c - b)</u>, we have the negative number <em>a</em> multiplied by the positive number <em>(c - b). </em>We know that the result of the <u>multiplication of a negative number by a positive number is negative. </u>

<u>Therefore  a (c - b) < 0</u>

Thus, the expression that is greater is the positive one which is a (b - c)

5 0
3 years ago
What is the length of the hypotenuse of the triangle when x=7?
Anika [276]

Answer:

c=57.8

Step-by-step explanation:

6*7+4=46

5*7=35

c= 46^2+35^2=57.80138

7 0
3 years ago
Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle
mario62 [17]

Step-by-step explanation:

The distance formula between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points.

A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}

If a ≤ b < c are the sides of the right triangle, then

a² + b² = c²

\sqrt5

used (\sqrt{a})^2=a for a ≥ 0.

AB^2+BC^2=AC^2 therefore ΔABC is a right triangle.

6 0
3 years ago
Solve for j.<br>-13j - 20 = -8j + 20​
aleksley [76]

Answer:

j = -8

Step-by-step explanation:

-13j - 20 = -8j + 20​

Add 13 j to each side

-13j+13j - 20 = -8j+13j + 20

-20 = 5j+20

subtract 20 from each side

-20-20 = 5j +20-20

-40 = 5j

Divide by 5

-40/5 = =5j/5

-8 =j

8 0
3 years ago
Look at the picture ​
Nikitich [7]

Answer:

c

Step-by-step explanation:

4 0
2 years ago
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