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3 years ago

If f(x)=x/2 and g(x) = x-3,what is the value of g(f(8))

Mathematics

2 answers:

pochemuha3 years ago

7 0

F(x) = x/2
g(x) = x - 3

f(8) = 8/2 = 4

g(f(x)) = 4 - 3 = 1

Answer g(f(8)) = 1

MArishka [77]3 years ago

3 0

Comment.
The first thing to do is find out what f(x) put into g(x) is and what it means.

Step One
Put f(x) into g(x). This means wherever you see an x in g(x) you put f(x)
g(x) = x - 3
g( f(x) ) = f(x) - 3
g( f(x) ) = x/2 - 3

Step Two
When you know what g(f(x)) you now put an 8 wherever you see an x.
Find g(f(8)) = x/2 - 3
g(f(8)) = 8/2 - 3
g(f(8)) = 4 - 3
g(f(8)) = 1

1 <<<<< answer.

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What is the solution for the equation 4x − 10 = 2x? x = ___. (Input whole number only).

White raven [17]

4x-10=2x subtract 2x from both sides

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3 years ago

Read 2 more answers

Kenny's scores the first 5 times he played a video game are listed below. 38, 51, 64, 77, 90 Kenny's scores follow a pattern. If

gayaneshka [121]

Kenny's score on his 72nd game played is 961

Solution:

Given that the first 5 score of Kenny are listed below:

38, 51, 64, 77, 90

Kenny's scores follow a pattern

To find: Kenny's score on his 72nd game played

Let us first find the pattern followed

38, 51, 64, 77, 90

Find the difference between terms

51 - 38 = 13

64 - 51 = 13

77 - 64 = 13

90 - 77 = 13

So the difference between terms is constant

So the sequence is arithmetic sequence

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

The formula for nth term of arithmetic sequence is given as:

$a_n = a_1 + (n-1)d$

$a_n$ = the nᵗʰ term in the sequence

$a_1$ = the first term in the sequence

d = the common difference between terms

Here d = 13 and $a_1 = 38$

So we get,

$a_n = 38 + (n-1) \times 13$

To find the score of 72nd game, substitute n = 72

$a_{72} = 38 + (72-1) \times 13\\\\a_{72} = 38 + 71 \times 13\\\\a_{72} = 38 + 923\\\\a_{72} = 961$

Thus Kenny's score on his 72nd game played is 961

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3 years ago

Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

General solution of cos θ = cos ∝ is θ = 2nπ±∝

Now The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

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Lubov Fominskaja [6]

Answer:

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Step-by-step explanation:

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astra-53 [7]

Answer:

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