solution: Mr. Schwartz will need to order more wheels after building 12 cars.
explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
Answer:
49/20 miles or 2.45 miles
Step-by-step explanation:
LCM(1,2,3,4,5,6,)=60
10/60+12/60+15/60+20/60+30/60+60/60=147/60=49/60 or 2.45
Answer:
1449/2691
Step-by-step explanation:
We must start from the fraction that is 7/13. Now, we know that it was simplified, with trial and error we can reach the result.
First, let's multiply both by 200:
7 * 200 = 1400
13 * 200 = 2600
1400 + 2600 = 4000
It means that we are missing 140, to reach the objective, that is, we are close, let's try 205 now:
7 * 205 = 1435
13 * 205 = 2665
1435 + 2665 = 4100
We get even closer, only 40 missing, let's try 207 below:
7 * 205 = 1449
13 * 205 = 2691
1449 + 2691 = 4140
We managed to get to the corresponding numbers, therefore the original fraction was 1449/2691
Answer:
9836523
is the answer. just check
