So distribute using distributive property
a(b+c)=ab+ac so
split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24
the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24
Answer:
solution
Step-by-step explanation:
This is the answer here u go have urhvhcgchchc
By using the information given on the graph, we can see that a = 3.
<h3>
How to find the value of a?</h3>
Here we have an exponential of the form:

And by looking at the graph, it passes through (0, 4) and (2, 36), so we can write:

From the first equation we get that p = 4, replacing that on the second one we get:

So we conclude that a = 3.
If you want to learn more about exponential equations:
brainly.com/question/11832081
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The first digit may be 1 or 8.
The second digit may be 1, 2, 4, 8.
The third digit may be 1, 3, 5, 7, 9.
There are 
The probability that this is the correct code is 