All categories

2 years ago

Which of the following best describes the intersection of two planes? (Points : 5)

1 answer:

4 0

<span>In geometry, planes are two-dimensional spaces which extend infinitely. If they do not intersect at all, they are considered parallel. However, if they do intersect, that intersection come in the form of an infinitely-extending collection of 1-dimensional points, which collectively form a line. As such, the answer is "line".</span>

You might be interested in

I don’t know the answer please help me

disa [49]

Answer:

Step-by-step explanation:

So fill in the variables and solve from there:

(5)(4)+2(3)^2 = ?

20 + (2)(9) = ?

20 + 18 = ?

? = 38

6 0

3 years ago

20 POINTS! What is the slope of the line through the points (2, 5) and (6, 13)?

sergejj [24]

Slope can be found using the formula $\frac{y2-y1}{x2-x1}$ .

$\frac{13-5}{6-2}$
$\frac{8}{4}
$
Slope = 2

So the slope of the line that passes through that point is 2.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

A store sells the basic model of a phone for $60 and the upgraded model for $200. It costs the store $10 to buy each basic model

ivolga24 [154]

Answer:

Step-by-step explanation:

(6*200)+(10*60)=1800

(6*50)+(10*10)=400

5 0

2 years ago

Mrrafil [7]

We are asked to express the diagonal of a rectangle in terms of the width in which the area of the polygon is equal to 13 square feet. The area of teh rectangle is equal to length times width. That is 13 = lw; diagonal using pythagorean theorem is sqrt ( l2 + w2). Thus d = sqrt ( (13/w)2 + w2) = sqrt ( (169/w2 + w2) = sqrt ( (169 + w4)/w2) = 1/w sqrt (169 + w4)

3 0

3 years ago

Read 2 more answers

4. Assume that the chances of a basketball player hitting a 3-pointer shot is 0.4 and the probability of hitting a free-throw is

vovikov84 [41]

Answer:

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

Step-by-step explanation:

For each 3-pointer shot, there are only two possible outcomes. Either the player makes it, or the player does not. The same is valid for free throws. This means that both the number of 3-pointers and free throws made are given by binomial distributions.

Since 3-pointers and free throws are independent, first we find the probability of making exactly 3 3-pointers out of 10, then the probability of making exactly 5 free throws out of 10, and then the probability that the player will make exactly 3 3-pointers and 5-free throws is the multiplication of these probabilities.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of making 3 3-pointers out of 10:

The chances of a basketball player hitting a 3-pointer shot is 0.4, which means that $p = 0.4$ . So this is $P(X = 3)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.21499$

Probability of making 5 free throws out of 10:

The probability of hitting a free-throw is 0.65, which means that $p = 0.65$ . The probability is $P(X = 5)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{10,5}.(0.65)^{5}.(0.35)^{5} = 0.15357$

Calculate the probability that the player will make exactly 3 3-pointers and 5-free throws.

0.21499*0.15537 = 0.0334

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

5 0

2 years ago