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Oxana [17]
2 years ago
15

What is the value of t in the equation 3(t − 4) = 2t + 1?

Mathematics
2 answers:
MariettaO [177]2 years ago
7 0

Answer: 13

Step-by-step explanation:

Distribute t.

Multiply 3 by each value in parentheses to get

3t - 12 = 2t + 1

Add 12 to both sides

3t = 2t + 13

Subtract 2t from both sides

t = 13

Mnenie [13.5K]2 years ago
5 0

Answer:

t = 13

Step-by-step explanation:

3(t-4)=2t+1\\\\3t-12=2t+1\\\\t-12=1\\\\t=13

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Find y when x equals 15 if y equals 6 when x equals 30
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X=15 and Y=?

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After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

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3 years ago
I need help with 1-32 it’s a test help ASAP thanks
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What’s in it for me will u give me vbucks
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The answer is: 7/7

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