Question

The centers of a 15 kg lead ball and a 130 g lead ball are separated by 6.0 cm.

Answer 1

Answer:

F = G m_{1}  m_{2}  / d^2

G = 6.67*10^-11 Nm^2/kg^2  

m_1 = 15kg  

m_2 = 130g = .13kg    

d = 6cm = 0.06m

F = 6.67*$10^{-11}$ * ((15*.13)/.06)

F = 2.16775e $10^{-11}$

Step-by-step explanation:

Answer 2

F = G$m_{1} m_{2}$ / d^2
G = 6.67*10^-11 Nm^2/kg^2   m_1 = 15kg    m_2 = 130g = .13kg    d = 6cm = 0.06m

F = 6.67*10^-11 * ((15*.13)/.06)
F = 2.16775$*10^{-11}$