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3 years ago

The centers of a 15 kg lead ball and a 130 g lead ball are separated by 6.0 cm.

Mathematics

2 answers:

Zigmanuir [339]3 years ago

7 0

Answer:

F = G m_{1} m_{2} / d^2

G = 6.67*10^-11 Nm^2/kg^2

m_1 = 15kg

m_2 = 130g = .13kg

d = 6cm = 0.06m

F = 6.67* $10^{-11}$ * ((15*.13)/.06)

F = 2.16775e $10^{-11}$

Step-by-step explanation:

Elina [12.6K]3 years ago

5 0

F = G $m_{1} m_{2}$ / d^2
G = 6.67*10^-11 Nm^2/kg^2 m_1 = 15kg m_2 = 130g = .13kg d = 6cm = 0.06m

F = 6.67*10^-11 * ((15*.13)/.06)
F = 2.16775 $*10^{-11}$

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