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3 years ago

PQ=20,RS=20 and the measure of ARC PT= 35 Find the measure of arc RS

1 answer:

4 0

If RS arc is = to the RS central angle then the RS arc would be 20 degrees, but if the RS is on the Circumference then the RS arc would be 40.

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I needdd helppppppppp real bad!!!!! Plwesss help!!! TYSMMMM!!

BaLLatris [955]

Soz man i use the metric system

6 0

4 years ago

Read 2 more answers

Can anyone help me figure out the answer to this

Alex17521 [72]

3x-11=17-4x add 4x to both sides

7x-11=17 add 11 to both sides

7x=28 divide both sides by 7

x=4

4 0

3 years ago

PLEASE HELP!!!!

LekaFEV [45]

Answer:

500

Step-by-step explanation:

It's a box with a square base, so let's say the width and length are x and the height is y.

The surface area of the box without the top is:

A = x² + 4xy

300 = x² + 4xy

The volume of the box is:

V = x²y

Solve for y in the first equation and substitute into the second:

y = (300 − x²) / 4x

V = x² (300 − x²) / 4x

V = x (300 − x²) / 4

V = 75x − ¼ x³

To optimize V, find dV/dx and set to 0:

dV/dx = 75 − ¾ x²

0 = 75 − ¾ x²

x = 10

So the volume of the box is:

V = 75x − ¼ x³

V = 500

The maximum volume is 500 cm³.

4 0

4 years ago

13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult

Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that $\frac{ab}{m}$ is and integer.

As m= vb, then $\frac{m}{b}$ is an integer, lets say $\frac{m}{b}$ =v; and as m=ua, then $\frac{m}{a}$ =u.

So $\frac{ab}{m}$ v= $\frac{ab}{m}$ $\frac{m}{b}$ =a, so $\frac{ab}{m}$ divides a; on the other hand, $\frac{ab}{m}$ u= $\frac{ab}{m}$ $\frac{m}{a}$ =b, so $\frac{ab}{m}$ divides b. From this we can conclude that $\frac{ab}{m}$ is a common divisor of a and b.

4 0

3 years ago

Find the measure of x<br> please no bots:(it’s easy

IceJOKER [234]

Answer:

Step-by-step explanation:

There are 6 equal angles that add up to 360 in that diagram. That means that if you divide 360 by 6, then you get 60.

Hope that this helps!

Edit: Thanks for the Brainliest!

6 0

3 years ago