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Answer:
What do you want me to do
Explanation:
Answer:
TAX_RATE = 0.20
STANDART_DEDUCTION = 10000.0
DEPENDENT_DEDUCTION = 3000.0
gross_income = float(input("Enter the gross income: "))
number_of_dependents = int(input("Enter the number of dependents: "))
income = gross_income - STANDART_DEDUCTION - (DEPENDENT_DEDUCTION * number_of_dependents)
tax = income * TAX_RATE
print ("The income tax is $" + str(round(tax, 2)))
Explanation:
Define the <em>constants</em>
Ask user to enter the <em>gross income</em> and <em>number of dependents</em>
Calculate the <em>income</em> using formula (income = gross_income - STANDART_DEDUCTION - (DEPENDENT_DEDUCTION * number_of_dependents))
Calculate the <em>tax</em>
Print the <em>tax</em>
<em />
round(number, number of digits) -> This is the general usage of the <em>round</em> function in Python.
Since we need <u>two digits of precision</u>, we need to modify the program as str(<u>round(incomeTax, 2</u>)).
Answer:
# include <iostream.h>
# include <stdio.h>
# include <string.h>
using namespace std;
class citizen
{
int i;
public string name[30];
public long int phonenumber[30];
public void addindividual(string name1)
{
If (i<=30)
{ int flag=0;
for(int j=0; j<=i;j++)
{
if (strcmp(name[i], name1)
{
flag=1;
}
else
{
flag=0;
}
}
If (flag)
{
if (i<30)
{
for(j=i+1;j<=30; j++)
{
cout<<"Enter the name:"; getchar(name[j]);
cout<<"Enter the phone number:"; cin>>phonenumber[j];
i++;
}
else
{
cout<<"The person already exists";
exit();
}
}
else
{
cout<<"array is full:";
exit();
}
}
}
Void main()
{
string str;
cout<<" Enter name:";
getline(cin, str); ;
citizen c1=new citizen();
c1.addindividual(name1);
}
Explanation:
With a little more effort you can make the program allow the user to enter any number of details, but less than 30 overall. We have used here flag, and as a programmer we know why we use the Flag. It is used to check whether certain Boolean condition is fulfilled or not. Here, we are checking whether a given name is present in the array of names, and if it is not present, we add that to the list. And if the name is present, we print, it already exist.
