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ludmilkaskok [199]
3 years ago
8

A cone has a diameter of 9 inches and a height of 12 inches. Find the volume of the cone to the nearest tenth.

Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0
1)
The formula for calculating the cone volume is: 
V =  \frac{ \pi *r^2*h}{3}

Data:
V (volume) = ?
h (height) → h = 12 in
d (diagonal) = 9 in , if: d = 2*r , soon: 9 = 2*r → 2r = 9 → r = 9/2 → r = 4.5 in
Use: \pi \approx 3.14

Solving:
V = \frac{ \pi *r^2*h}{3}
V = \frac{ 3.14 *4.5^2*12}{3}
V = \frac{ 3.14 *20.25*12}{3}
V = \frac{763.02}{3}
\boxed{\boxed{V = 254.34\:in^3}}\end{array}}\qquad\quad\checkmark

2)
The circle area formula is: A =  \pi * r^2

Data:
A (area) = ?
d (diagonal) = 19 Km , if: d = 2*r , soon: 19 = 2*r → 2r = 19 → r = 19/2 → r = 9.5 Km
Use: \pi \approx 3.14

Solving:
A = \pi * r^2
A = 3.14*9.5^2
A = 3.14*90.25
\boxed{\boxed{A = 283.385\:Km^2}}\end{array}}\qquad\quad\checkmark


3) False, because it's the volume, the number of cubic units needed to fill a space. 
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Helppp I really need this question answered
Ne4ueva [31]

Answer:

32.5 units²

Step-by-step explanation:

We can find the area by dividing the figure into two shapes. If we solve for the area of a square and a triangle, we can add them together.

First, we can solve for the area of the 5x5 square. To find the area, we can multiply the two dimensions.

5 · 5 = 25 units²

Next, we can find the area of the triangle. It has an equal height to the square, so the height of the triangle is 5 units. The width isn't specified. Instead, we are shown that the width of both the square and the triangle equals 8 units. If we subtract the width of the square from the total, we can find the width of the triangle, too.

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So, the height and the width of the triangle are 5x3. To find the area we can multiply these together, and then divide the product by two.

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The area of the triangle is 7.5 units².

Finally, we can add the area of the triangle and the square together.

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The area of the figure, then, is 32.5 units².

The answer is the last option.

I hope this helps ^^

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