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ludmilkaskok [199]
3 years ago
8

A cone has a diameter of 9 inches and a height of 12 inches. Find the volume of the cone to the nearest tenth.

Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0
1)
The formula for calculating the cone volume is: 
V =  \frac{ \pi *r^2*h}{3}

Data:
V (volume) = ?
h (height) → h = 12 in
d (diagonal) = 9 in , if: d = 2*r , soon: 9 = 2*r → 2r = 9 → r = 9/2 → r = 4.5 in
Use: \pi \approx 3.14

Solving:
V = \frac{ \pi *r^2*h}{3}
V = \frac{ 3.14 *4.5^2*12}{3}
V = \frac{ 3.14 *20.25*12}{3}
V = \frac{763.02}{3}
\boxed{\boxed{V = 254.34\:in^3}}\end{array}}\qquad\quad\checkmark

2)
The circle area formula is: A =  \pi * r^2

Data:
A (area) = ?
d (diagonal) = 19 Km , if: d = 2*r , soon: 19 = 2*r → 2r = 19 → r = 19/2 → r = 9.5 Km
Use: \pi \approx 3.14

Solving:
A = \pi * r^2
A = 3.14*9.5^2
A = 3.14*90.25
\boxed{\boxed{A = 283.385\:Km^2}}\end{array}}\qquad\quad\checkmark


3) False, because it's the volume, the number of cubic units needed to fill a space. 
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Solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Step-by-step explanation:

We need to solve the inequality: -3q+12\geq 4q-30 and find value of q

Solving:

-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6

So, solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Keywords: Solving inequality

Learn more about solving inequality at:

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