Answer:
Melanie's account balance now is $3182.87.
Step-by-step explanation:
Given:
Amount of money in her account = $3106.12
Amount deposited on Thursday = $85
Amount spent for lunch on Friday = $8.25
We need to find the remaining balance in Melanie's account.
Solution:
Now we know that;
Remaining balance in her account is equal to Amount of money in her account plus Amount deposited on Thursday minus Amount spent for lunch on Friday.
framing in equation form we get;
Remaining balance in her account = 
Hence Melanie's account balance now is $3182.87.
Answer:
Step-by-step explanation:
lets foil it and complete the square
x^2+4x-12x-48=9
x^2-8x=57
(-8/.5)^2=16
(x-4)^2-73
Answer:
P = 28cm
Step-by-step explanation:
The general formula for the perimeter of a rectangle is: 'P = 2L +2W' (L being the length and W being the width of the rectangle.)
Step 1: Substitute L = 7, W = 7 into the general formula.
P = 2(7) + 2(7)
Step 2: Solve!
P = 2 x 7 + 2 x 7
P = 14 + 14
P = 28
Step 3: Don't forget to add the units of measurement! (In this case 'cm')
Therefore, P = 28cm
Answer:
dy = 2(c-3y)dt
Step-by-step explanation:
Given the Equilibrium solutions at y=0 and y=3, y' > 0 for 0 < y < 3; and y' < 0 for -inf < y < 0 and 3 < y < inf.
from the boundary conditions given,
- since our task is to find the differential of y wrt t i.e dy/dt,
- from the first condition, it implies that if we are to assume from the range of values of y = {0,1,2}, assume when y =0, t = 0
from y = 3, y-3 = 0
integrate wrt dy i.e Integral (y-3) dy = 0
y2/2 - 3y + c = 0, where c is the constant of integration
hence, y2-6y+2c = 0
from the equation, above for the differential of y (dy/dx) to be greater than zero, for the boundary conditions, 0 < y < 3, the constant of integrative must be negative or zero.
hence the equation y2-6y+2c = 0 can be written as
dy/dx =2c-6y, dy = 2(c-3y)dt
in terms of t
