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Nikitich [7]
3 years ago
11

PLEASE HELP ASAP PLEASE

Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

The equation that represents the line passing through the point (2, -4) with a slope of one half is

f(x) = \frac{1}{2}x - 5

Step-by-step explanation:

The equation of a line can be described by a first order equation in the following format:

f(x) = ax + b

In which a is the slope of the line.

Solution:

The line slope is \frac{1}{2}, so a = \frac{1}{2}.

The equation of the line now is:

f(x) = \frac{1}{2}x + b

The problem states that the line passes through the point(2,-4). This means that when x = 2, f(x) = -4

So:

f(x) = \frac{1}{2}x + b

-4 = \frac{1}{2}*(2) + b

-4 = 1 + b

b = -5

So, the equation that represents the line passing through the point (2, -4) with a slope of one half is

f(x) = \frac{1}{2}x - 5

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Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).
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Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>
  • The critical points of a function are the values of x for which:

f^{\prime}(x) = 0

In this problem, the function is:

f(x) = x^3 + ax^2 + b

Hence, the derivative is:

f^{\prime}(x) = 3x^2 + 2ax

Then:

f^{\prime}(x) = 0

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x = 0

3x + 2a = 0

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Since the critical point is at x = 2, we have that:

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Then:

f(x) = x^3 - 3x^2 + b

Critical point at (2,3) means that when x = 2, y = 3, then:

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You can learn more about the critical point concept at brainly.com/question/2256078

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