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Nikitich [7]
3 years ago
11

PLEASE HELP ASAP PLEASE

Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

The equation that represents the line passing through the point (2, -4) with a slope of one half is

f(x) = \frac{1}{2}x - 5

Step-by-step explanation:

The equation of a line can be described by a first order equation in the following format:

f(x) = ax + b

In which a is the slope of the line.

Solution:

The line slope is \frac{1}{2}, so a = \frac{1}{2}.

The equation of the line now is:

f(x) = \frac{1}{2}x + b

The problem states that the line passes through the point(2,-4). This means that when x = 2, f(x) = -4

So:

f(x) = \frac{1}{2}x + b

-4 = \frac{1}{2}*(2) + b

-4 = 1 + b

b = -5

So, the equation that represents the line passing through the point (2, -4) with a slope of one half is

f(x) = \frac{1}{2}x - 5

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Step-by-step explanation:

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aleksley [76]

Answer:

219.91cm²

Step-by-step explanation:

The question is not properly structured. Here is the complete question.

A sector with a radius of 10cm and has a central angle of 252°. Calculate the area of the sector.

Area of a sector = theta/360 × πr²

theta is the angle substended by the circle

r is the radius of the circle.

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theta = 252°

Area of a sector = 252°/360° × π(10)²

Area of a sector = 252/360 × 100π

Area of a sector = 79168.13.360

Answer:

Step-by-step explanation:

The question is not properly structured. Here is the complete question.

A sector with a radius of 10cm and has a central angle of 252°. Calculate the area of the sector.

Area of a sector = theta/360 × πr²

theta is the angle substended by the circle

r is the radius of the circle.

Given radius = 10cm

theta = 252°

Area of a sector = 252°/360° × π(10)²

Area of a sector = 252/360 × 100π

Area of the sector = 219.91cm²

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4 years ago
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